答复: [PATCH] sched/core: return prio_less() directly in __sched_core_less

["Li,Rongqing" <lirongqing@baidu.com>]

Ping

-Li

> -----邮件原件-----
> 发件人: Li,Rongqing <lirongqing@baidu.com>
> 发送时间: 2021年8月24日 18:19
> 收件人: mingo@redhat.com; peterz@infradead.org; juri.lelli@redhat.com;
> vincent.guittot@linaro.org; linux-kernel@vger.kernel.org; Li,Rongqing
> <lirongqing@baidu.com>
> 主题: [PATCH] sched/core: return prio_less() directly in __sched_core_less
> 
> return prio_less() directly to avoid unnecessary checking
> 
> Signed-off-by: Li RongQing <lirongqing@baidu.com>
> ---
>  kernel/sched/core.c |    5 +----
>  1 files changed, 1 insertions(+), 4 deletions(-)
> 
> diff --git a/kernel/sched/core.c b/kernel/sched/core.c index 2d9ff40..73478c9
> 100644
> --- a/kernel/sched/core.c
> +++ b/kernel/sched/core.c
> @@ -140,10 +140,7 @@ static inline bool __sched_core_less(struct task_struct
> *a, struct task_struct *
>  		return false;
> 
>  	/* flip prio, so high prio is leftmost */
> -	if (prio_less(b, a, task_rq(a)->core->core_forceidle))
> -		return true;
> -
> -	return false;
> +	return prio_less(b, a, task_rq(a)->core->core_forceidle);
>  }
> 
>  #define __node_2_sc(node) rb_entry((node), struct task_struct, core_node)
> --
> 1.7.1