Re: wait() and strace -f

[OGAWA Hirofumi <hirofumi@mail.parknet.co.jp>]

Kurt Roeckx <Q@ping.be> writes:

> int     main()
> {
>         int     i;
> 
>         if (!fork())
>         {
>                 /* Child 1. */
>                 return 0;
>         }
> 
>         if (!fork())
>         {
>                 /* Child 2. */
>                 sleep(10);
>                 return 0;
>         }
> 
>         /* Parent. */
>         sleep(1);
>         wait(&i);
>         return 0;
> }
> 
> Without strace -f, this program stops after 1 second and the
> second child still lives for 9 seconds.  With strace -f this
> program stops after 10 second after the second child died.
> 
> I think it's related to strace being the "real" parent of the
> child.  But that doesn't really explain why I need 2 childs.

Probably, it's feature (or bug) of strace. If the trace process has
child, trace of a child is continued before wait() of parent. Then,
exit() of the child process continue wait() of parent.

>         if (!fork())
>         {
>                 /* Child 1. */
		  sleep(2);
>                 return 0;
>         }

The above continued the parent after 2 seconds.
-- 
OGAWA Hirofumi <hirofumi@mail.parknet.co.jp>