Why isn't init PID 1?

Why isn't init PID 1?

[Paul Powell]

Hello,

I have a bootable linux CD that runs a custom init. 
Under most versions of linux init runs as process ID
one.  Under my bootable CD, it runs as process ID 15. 
I need it to run as PID 1 so that I can execute a
kill(-1,15) without killing init.

The boot CD uses and initrd image to load drivers. 
The linuxrc file looks like:

#!/bin/sash

aliasall

echo "Loading aic7xxx module"
insmod /lib/aic7xxx.o
echo "Loading ips module"
insmod /lib/ips.o ips=ioctlsize:512000
echo "Loading sg module"
insmod /lib/sg.o
echo "Loading FAT modules"
insmod /lib/fat.o
insmod /lib/vfat.o

echo "Mounting /proc"
mount -t proc /proc /proc
init
umount /proc

Does it run as PID 15 because I execute insmod and
mount before running init?

Thanks,
Paul

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Re: Why isn't init PID 1?

[Patrizio Bruno]

Yes, in this situation "sash" is the process with pid '1', you should run this script through init and not viceversa, the first process launched takes pid 1.

P.

On Wed, 31 Jan 2001, Paul Powell wrote:

> Hello,
> 
> I have a bootable linux CD that runs a custom init. 
> Under most versions of linux init runs as process ID
> one.  Under my bootable CD, it runs as process ID 15. 
> I need it to run as PID 1 so that I can execute a
> kill(-1,15) without killing init.
> 
> The boot CD uses and initrd image to load drivers. 
> The linuxrc file looks like:
> 
> #!/bin/sash
> 
> aliasall
> 
> echo "Loading aic7xxx module"
> insmod /lib/aic7xxx.o
> echo "Loading ips module"
> insmod /lib/ips.o ips=ioctlsize:512000
> echo "Loading sg module"
> insmod /lib/sg.o
> echo "Loading FAT modules"
> insmod /lib/fat.o
> insmod /lib/vfat.o
> 
> echo "Mounting /proc"
> mount -t proc /proc /proc
> init
> umount /proc
> 
> Does it run as PID 15 because I execute insmod and
> mount before running init?
> 
> Thanks,
> Paul
> 
> __________________________________________________
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Re: Why isn't init PID 1?

[Igmar Palsenberg]

On Wed, 31 Jan 2001, Paul Powell wrote:

> Hello,
> 
> I have a bootable linux CD that runs a custom init. 
> Under most versions of linux init runs as process ID
> one.  Under my bootable CD, it runs as process ID 15. 
> I need it to run as PID 1 so that I can execute a
> kill(-1,15) without killing init.
> 
> The boot CD uses and initrd image to load drivers. 
> The linuxrc file looks like:
> 
> #!/bin/sash
> 
> aliasall
> 
> echo "Loading aic7xxx module"
> insmod /lib/aic7xxx.o
> echo "Loading ips module"
> insmod /lib/ips.o ips=ioctlsize:512000
> echo "Loading sg module"
> insmod /lib/sg.o
> echo "Loading FAT modules"
> insmod /lib/fat.o
> insmod /lib/vfat.o
> 
> echo "Mounting /proc"
> mount -t proc /proc /proc
> init
> umount /proc
> 
> Does it run as PID 15 because I execute insmod and
> mount before running init?

Yes. First program to run get PID 1. 

Solution : fork() in init and load the modules in the child.



	Igmar

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Re: Why isn't init PID 1?

[H. Peter Anvin]

Followup to:  <Pine.LNX.4.21.0102010057470.11152-100000@server.serve.me.nl>
By author:    Igmar Palsenberg <maillist@chello.nl>
In newsgroup: linux.dev.kernel
> 
> Yes. First program to run get PID 1. 
> 
> Solution : fork() in init and load the modules in the child.
> 

Or finish your script with "exec init".

	-hpa
-- 
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"Unix gives you enough rope to shoot yourself in the foot."
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