RE: linux interprets an fcntl int arg as long

David Laight
2022-11-01T13:35:38Z

From: David Laight
> Sent: 01 November 2022 13:30
>
> From: Mark Rutland
> > Sent: 01 November 2022 13:13
> >
> > On Tue, Nov 01, 2022 at 12:19:51PM +0000, David Laight wrote:
> > > From: 'Szabolcs Nagy' <szabolcs.nagy@arm.com>
> > > > Sent: 01 November 2022 11:45
> > > >
> > > > The 11/01/2022 10:02, David Laight wrote:
> > > > > From: Szabolcs Nagy
> >
> > > > kernel code:
> > > > ------------
> > > > SYSCALL_DEFINE3(fcntl, unsigned int, fd, unsigned int, cmd, unsigned long, arg)
> > > > {
> > >
> > > That is just a wrapper and calls do_fcntl().
> > > which needs changing to be add:
> > > arg &= ~0U;
> > > before the switch(cmd) {
> >
> > Just to check, do you mean the switch in do_fcntl(), or the switch within memfd_fcntl() ?
> >
> > The former handles other APIs which do expect arg to be a long (e.g.
> > F_SET_RW_HINT and F_GET_RW_HINT expect it to hold a full 64-bit pointer), so
> > that'd break things.
>
> The assignment to argv is earlier.

Clearly I meant argp :-)

Alternatively all the helper functions should be changed to
have an 'unsigned int' argument instead of 'unsigned long'.

That might show up any that try to read user buffers.

David

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