Re: [PATCH 1/6] sched_ext: idle: Extend topology optimizations to all tasks

[Andrea Righi <arighi@nvidia.com>]

On Mon, Mar 17, 2025 at 08:22:35AM -1000, Tejun Heo wrote:
> Hello,
> 
> On Mon, Mar 17, 2025 at 06:53:24PM +0100, Andrea Righi wrote:
> > +/*
> > + * Return the subset of @cpus that task @p can use or NULL if none of the
> > + * CPUs in the @cpus cpumask can be used.
> > + */
> > +static const struct cpumask *task_cpumask(const struct task_struct *p, const struct cpumask *cpus,
> > +					  struct cpumask *local_cpus)
> 
> task_cpus_allowed_and()? It also would help to add comment explaining the
> parameters as the function is a bit unusual.

Ack.

> 
> > +{
> > +	/*
> > +	 * If the task is allowed to run on all CPUs, simply use the
> > +	 * architecture's cpumask directly. Otherwise, compute the
> > +	 * intersection of the architecture's cpumask and the task's
> > +	 * allowed cpumask.
> > +	 */
> > +	if (!cpus || p->nr_cpus_allowed >= num_possible_cpus() ||
> > +	    cpumask_subset(cpus, p->cpus_ptr))
> > +		return cpus;
> > +
> > +	if (!cpumask_equal(cpus, p->cpus_ptr) &&
> 
> Hmm... isn't this covered by the preceding cpumask_subset() test? Here, cpus
> is not a subset of p->cpus_ptr, so how can it be the same as p->cpus_ptr?

Oh that's right, I missed that between all the refactoring, thanks for
catching it. Will remove it.

> 
> > +	    cpumask_and(local_cpus, cpus, p->cpus_ptr))
> > +		return local_cpus;
> > +
> > +	return NULL;
> 
> and return values need some explanation too.

Ok.

Thanks,
-Andrea