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* irq 0?
@ 2005-11-07 11:54 Miles Bader
  2005-11-07 12:25 ` Ian Campbell
  0 siblings, 1 reply; 3+ messages in thread
From: Miles Bader @ 2005-11-07 11:54 UTC (permalink / raw)
  To: linux-kernel

I notice that arch/v850/kernel/irq.c has been updated with a
"show_interrupts" function; in this function it contains the following
bit of code:


	if (i == 0) {
		seq_puts(p, "           ");
		for (i=0; i < 1 /*smp_num_cpus*/; i++)
			seq_printf(p, "CPU%d       ", i);
		seq_putc(p, '\n');
	}

	if (i < NR_IRQS) {
                ... show interrupt i ...
	} else if (i == NR_IRQS)
		seq_printf(p, "ERR: %10lu\n", irq_err_count);

where "i" is iterated (by procfs) from 0...NR_IRQS.

On the v850, irq 0 is a real interrupt, so this doesn't really work
properly -- it doesn't display an entry for irq 0.

Is it now illegal for irq 0 to be a real interrupt (was it illegal before)?
Or is the procfs code just bogus?

Thanks,

-miles
-- 
Occam's razor split hairs so well, I bought the whole argument!

^ permalink raw reply	[flat|nested] 3+ messages in thread

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2005-11-07 11:54 irq 0? Miles Bader
2005-11-07 12:25 ` Ian Campbell
2005-11-07 12:57   ` Miles Bader

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