Re: initialize a mutex into locked state?

Oleg Drokin
2016-06-17T14:25:08Z

On Jun 17, 2016, at 10:19 AM, Peter Zijlstra wrote:

> On Fri, Jun 17, 2016 at 10:14:10AM -0400, Oleg Drokin wrote:
>>
>> On Jun 17, 2016, at 4:25 AM, Peter Zijlstra wrote:
>>
>>> On Wed, Jun 15, 2016 at 02:23:35PM -0400, Oleg Drokin wrote:
>>>> Hello!
>>>>
>>>> To my surprise I found out that it's not possible to initialise a mutex into
>>>> a locked state.
>>>> I discussed it with Arjan and apparently there's no fundamental reason
>>>> not to allow this.
>>>
>>> There is. A mutex _must_ have an owner. If you can initialize it in
>>> locked state, you could do so statically, ie. outside of the context of
>>> a task.
>>
>> What's wrong with disallowing only static initializers, but allowing dynamic ones?
>> Then there is a clear owner.
>
> At which point, what wrong with the simple:
>
> mutex_init(&m);
> mutex_lock(&m);
>
> Sequence? Its obvious, has clear semantics and doesn't extend the API.

The problem is:

spin_lock(somelock);
structure = some_internal_list_lookup(list);
if (structure)
goto out;

init_new_structure(new_structure);
mutex_init(&new_structure->s_mutex);
mutex_lock(&new_structure->s_mutex); // XXX CANNOT DO THIS UNDER SPINLOCK!

list_add(list, new_structure->s_list);
structure = new_structure;
out:
spin_unlock(somelock);
return structure;