[PATCH 3.16 095/306] mfd: 88pm80x: Double shifting bug in suspend/resume

Ben Hutchings
2017-02-15T23:24:48Z

From: Dan Carpenter <dan.carpenter@oracle.com>

commit 9a6dc644512fd083400a96ac4a035ac154fe6b8d upstream.

set_bit() and clear_bit() take the bit number so this code is really
doing "1 << (1 << irq)" which is a double shift bug. It's done
consistently so it won't cause a problem unless "irq" is more than 4.

Fixes: 70c6cce04066 ('mfd: Support 88pm80x in 80x driver')
Signed-off-by: Dan Carpenter <dan.carpenter@oracle.com>
Signed-off-by: Lee Jones <lee.jones@linaro.org>
Signed-off-by: Ben Hutchings <ben@decadent.org.uk>
---
include/linux/mfd/88pm80x.h | 4 ++--
1 file changed, 2 insertions(+), 2 deletions(-)

--- a/include/linux/mfd/88pm80x.h
+++ b/include/linux/mfd/88pm80x.h
@@ -349,7 +349,7 @@ static inline int pm80x_dev_suspend(stru
int irq = platform_get_irq(pdev, 0);

if (device_may_wakeup(dev))
- set_bit((1 << irq), &chip->wu_flag);
+ set_bit(irq, &chip->wu_flag);

return 0;
}
@@ -361,7 +361,7 @@ static inline int pm80x_dev_resume(struc
int irq = platform_get_irq(pdev, 0);

if (device_may_wakeup(dev))
- clear_bit((1 << irq), &chip->wu_flag);
+ clear_bit(irq, &chip->wu_flag);

return 0;
}