Re: 64-bit modulus operation in a 32-bit kernel

Andreas Schwab
2012-04-24T19:15:27Z

Alan Stern <stern@rowland.harvard.edu> writes:

> I need to compute the remainder when a 64-bit quantity is divided by a
> small value (126 in this case). The % operator doesn't work in an
> x86/32 kernel. What's the Right Way to do it?

#include <asm/div64.h>

do_div(n,base) returns the remainder.

Andreas.

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Andreas Schwab, schwab@linux-m68k.org
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