From mboxrd@z Thu Jan 1 00:00:00 1970 From: Yang Xu Date: Fri, 2 Aug 2019 18:12:58 +0800 Subject: [LTP] [PATCH] cgroup_regression_test.sh: fix test_5 possible mount failure because of cgroup hierarchy In-Reply-To: <5D2D681D.1050909@cn.fujitsu.com> References: <1560250815-2308-1-git-send-email-xuyang2018.jy@cn.fujitsu.com> <5D2D681D.1050909@cn.fujitsu.com> Message-ID: <5D440CAA.9080701@cn.fujitsu.com> List-Id: MIME-Version: 1.0 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: 7bit To: ltp@lists.linux.it Hi Ping. :-) > Hi > > Ping. :-) > >> Currently, if systems doesn't mount subsys1,subsys2 and the hierarchy is not equal to 0, running it >> reports the following error: >> >> mount: xxx is already mounted or /tmp/ltp-wPw08anmTI/LTP_cgroup_regression_test.V4jf0qrS7z/cgroup busy >> cgroup_regression_test 5 TFAIL: mount net_prio and pids failed >> >> It fails because libcgroup doesn't permmit destroy cgroup subsystem hierarchies. >> Simple umnout does not destroy the hierarchies. They still live inside kernel! >> >> When hierarchy is equal to 0 in /proc/cgroups, we can mount them together on >> a new mountpoint. >> >> I add a check for subsystem hierarchy and get subsystem from head. >> >> Notice: >> more information about"Bug 612805 - cgroup: mount: none already mounted or /cgroups busy" >> >> Signed-off-by: Yang Xu >> --- >> .../cgroup/cgroup_regression_test.sh | 18 +++++++++++++----- >> 1 file changed, 13 insertions(+), 5 deletions(-) >> >> diff --git a/testcases/kernel/controllers/cgroup/cgroup_regression_test.sh b/testcases/kernel/controllers/cgroup/cgroup_regression_test.sh >> index e197f5d3f..38cb760c2 100755 >> --- a/testcases/kernel/controllers/cgroup/cgroup_regression_test.sh >> +++ b/testcases/kernel/controllers/cgroup/cgroup_regression_test.sh >> @@ -252,8 +252,10 @@ test5() >> return >> fi >> >> - local subsys1=`tail -n 1 /proc/cgroups | awk '{ print $1 }'` >> - local subsys2=`tail -n 2 /proc/cgroups | head -1 | awk '{ print $1 }'` >> + local subsys1=`head -2 /proc/cgroups | tail -n 1 | awk '{ print $1 }'` >> + local subsys1_hierarchy=`head -2 /proc/cgroups | tail -n 1 | awk '{ print $2 }'` >> + local subsys2=`head -3 /proc/cgroups | tail -n 1 | awk '{ print $1 }'` >> + local subsys2_hierarchy=`head -3 /proc/cgroups | tail -n 1 | awk '{ print $2 }'` >> >> # Accounting here for the fact that the chosen subsystems could >> # have been already previously mounted at boot time: in such a >> @@ -267,10 +269,16 @@ test5() >> if [ -z "$mounted" ]; then >> mntpoint=cgroup >> failing=$subsys1 >> - mount -t cgroup -o $subsys1,$subsys2 xxx $mntpoint/ >> + mount -t cgroup -o $subsys1,$subsys2 xxx $mntpoint/ 2>/dev/null >> + # Even subsystem has not been mounted, it still live in kernel. >> + # So we will get EBUSY when both mount subsys1 and subsys2 if >> + # hierarchy isn't equal to 0. >> if [ $? -ne 0 ]; then >> - tst_res TFAIL "mount $subsys1 and $subsys2 failed" >> - return >> + if [ "$subsys1_hierarchy" = 0 -a "$subsys2_hierarchy" = 0 ]; then >> + tst_res TFAIL "mount $subsys1 and $subsys2 failed" >> + return >> + fi >> + failing=$subsys1,$subsys2 >> fi >> else >> # Use the pre-esistent mountpoint as $mntpoint and use a