Re: [PATCH]: Schedule correct qdisc in watchdog.

[Jarek Poplawski <jarkao2@gmail.com>]

On Mon, Aug 18, 2008 at 03:10:03AM -0700, David Miller wrote:
> From: Jarek Poplawski <jarkao2@gmail.com>
> Date: Mon, 18 Aug 2008 09:47:27 +0000
> 
> > Maybe I wrote this wrong. wd->qdisc stores qdisc from the
> > qdisc_watchdog_init() time, and this could be &noop_qdisc.
> > So qdisc_root() would schedule wrong qdisc later. BTW, my
> > version would probably do the same for root qdisc, but in
> > these tests there was a problem with leafs.
> 
> qdisc_watchdog_init() is only invoked by:
> 
> net/sched/sch_cbq.c:	qdisc_watchdog_init(&q->watchdog, sch);
> net/sched/sch_hfsc.c:	qdisc_watchdog_init(&q->watchdog, sch);
> net/sched/sch_htb.c:	qdisc_watchdog_init(&q->watchdog, sch);
> net/sched/sch_netem.c:	qdisc_watchdog_init(&q->watchdog, sch);
> net/sched/sch_tbf.c:	qdisc_watchdog_init(&q->watchdog, sch);
> 
> These "q" things are the scheduler private structs, and 'sch' of the
> qdisc type indicated by the source file the code in question resides
> :-)
> 
> This watchdog is different from the TX timeout watchdog which is
> implemented in net/sch/sch_generic.c, which you may be confusing this
> qdisc_watchdog_init() one with.

I don't think I wrote anything which could suggest I confused these
watchdogs.

> 
> The watchdog we are discussing here is purely for qdiscs where time
> based events modify qdisc state (such as making new quotas available
> for a flow, thus making certain packets eligible for scheduling that
> were not beforehand)
> 
> So really, it cannot be &noop_qdisc as far as I can see.
> :-)

Sure, ->sch is never &noop_qdisc, but your qdisc_root(sch) most
probably is at the moment of qdisc_watchdog_init(). My version
can do the same if eg. htb is root qdisc because at the moment
of qdisc_create() qdisc_sleeping could be &noop_qdisc as well.
But, in case we have a qdisc_sleeping already, it should work.

So these patches will stop break things, but these qdisc_watchdog()
calls would be sometimes/always useless.

Jarek P.