[PATCH 11/14] netfilter: nf_tables: return EBUSY if device already belongs to flowtable

[Pablo Neira Ayuso <pablo@netfilter.org>]

If the netdevice is already part of a flowtable, return EBUSY. I cannot
find a valid usecase for having two flowtables bound to the same
netdevice. We can still have two flowtable where the device set is
disjoint.

Signed-off-by: Pablo Neira Ayuso <pablo@netfilter.org>
---
 net/netfilter/nf_tables_api.c | 18 +++++++++++++++++-
 1 file changed, 17 insertions(+), 1 deletion(-)

diff --git a/net/netfilter/nf_tables_api.c b/net/netfilter/nf_tables_api.c
index 8b9fe30de0cd..43acdeef045d 100644
--- a/net/netfilter/nf_tables_api.c
+++ b/net/netfilter/nf_tables_api.c
@@ -5037,9 +5037,9 @@ static int nf_tables_newflowtable(struct net *net, struct sock *nlsk,
 {
 	const struct nfgenmsg *nfmsg = nlmsg_data(nlh);
 	const struct nf_flowtable_type *type;
+	struct nft_flowtable *flowtable, *ft;
 	u8 genmask = nft_genmask_next(net);
 	int family = nfmsg->nfgen_family;
-	struct nft_flowtable *flowtable;
 	struct nft_table *table;
 	struct nft_ctx ctx;
 	int err, i, k;
@@ -5099,6 +5099,22 @@ static int nf_tables_newflowtable(struct net *net, struct sock *nlsk,
 		goto err3;
 
 	for (i = 0; i < flowtable->ops_len; i++) {
+		if (!flowtable->ops[i].dev)
+			continue;
+
+		list_for_each_entry(ft, &table->flowtables, list) {
+			for (k = 0; k < ft->ops_len; k++) {
+				if (!ft->ops[k].dev)
+					continue;
+
+				if (flowtable->ops[i].dev == ft->ops[k].dev &&
+				    flowtable->ops[i].pf == ft->ops[k].pf) {
+					err = -EBUSY;
+					goto err4;
+				}
+			}
+		}
+
 		err = nf_register_net_hook(net, &flowtable->ops[i]);
 		if (err < 0)
 			goto err4;
-- 
2.11.0