RE: violating function pointer signature

David Laight
2020-11-19T17:43:10Z

From: Segher Boessenkool
> Sent: 19 November 2020 16:35
...
> I just meant "valid C language code as defined by the standards". Many
> people want all UB to just go away, while that is *impossible* to do for
> many compilers: for example where different architectures or different
> ABIs have contradictory requirements.

Some of the UB in the C language are (probably) there because
certain (now obscure) hardware behaved that way.
For instance integer arithmetic may saturate on overflow
(or do even stranger things if the sign is a separate bit).
I'm not quite sure it was ever possible to write a C compiler
for a cpu that processed numbers in ASCII (up to 10 digits),
binary arithmetic was almost impossible.
There are also the CPU that only have 'word' addressing - so
that 'pointers to characters' take extra instructions.

ISTM that a few years ago the gcc developers started looking
at some of these 'UB' and decided they could make use of
them to make some code faster (and break other code).

One of the problems with UB is that whereas you might expect
UB arithmetic to generate an unexpected result and/or signal
it is completely open-ended and could fire an ICBM at the coder.

David

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