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From: Jan Kiszka <jan.kiszka@web.de>
To: netdev@vger.kernel.org
Cc: Jiri Benc <jbenc@suse.cz>, Ivo Van Doorn <ivdoorn@gmail.com>,
	rt2400-devel@lists.sourceforge.net
Subject: d80211: How does TX flow control work?
Date: Tue, 02 Jan 2007 14:08:21 +0100	[thread overview]
Message-ID: <459A5945.80909@web.de> (raw)

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Hi,

can someone explain how TX flow control in d80211 is supposed to work? I
failed to understand the full design so far.

What I (think to) understand is that a low-level drivers call
ieee80211_stop_queue() if they run out of buffers. That flips a
per-queue bit (IEEE80211_LINK_STATE_XOFF), prevents that any further
frame is passed to the low-level TX routine, and can cause that up to
*one* packet per queue is stored in
ieee80211_local::pending_packets[queue]. But it looks to me like nothing
prevents ieee80211_tx() being invoked even in case that there is already
some stuff in that single-packet storage.

That in turn triggers WARN_ONs in ieee80211_tx() under high load for me
(with rt2500usb). And it should also cause orphaned skbs because the
storage is overwritten in that case. Either I'm blind or something is
fishy...

Jan


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             reply	other threads:[~2007-01-02 13:08 UTC|newest]

Thread overview: 9+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2007-01-02 13:08 Jan Kiszka [this message]
2007-01-03 17:52 ` d80211: How does TX flow control work? Jiri Benc
2007-01-03 18:10   ` Jan Kiszka
2007-01-03 18:18     ` Jiri Benc
2007-01-03 18:50       ` Jan Kiszka
2007-01-07  0:00         ` Jan Kiszka
2007-01-08 20:18           ` Jan Kiszka
2007-01-10 18:20             ` Jiri Benc
2007-01-10 18:29               ` Simon Barber

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