From: Jan Kiszka <jan.kiszka@web.de>
To: netdev@vger.kernel.org
Cc: Jiri Benc <jbenc@suse.cz>, Ivo Van Doorn <ivdoorn@gmail.com>,
rt2400-devel@lists.sourceforge.net
Subject: d80211: How does TX flow control work?
Date: Tue, 02 Jan 2007 14:08:21 +0100 [thread overview]
Message-ID: <459A5945.80909@web.de> (raw)
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Hi,
can someone explain how TX flow control in d80211 is supposed to work? I
failed to understand the full design so far.
What I (think to) understand is that a low-level drivers call
ieee80211_stop_queue() if they run out of buffers. That flips a
per-queue bit (IEEE80211_LINK_STATE_XOFF), prevents that any further
frame is passed to the low-level TX routine, and can cause that up to
*one* packet per queue is stored in
ieee80211_local::pending_packets[queue]. But it looks to me like nothing
prevents ieee80211_tx() being invoked even in case that there is already
some stuff in that single-packet storage.
That in turn triggers WARN_ONs in ieee80211_tx() under high load for me
(with rt2500usb). And it should also cause orphaned skbs because the
storage is overwritten in that case. Either I'm blind or something is
fishy...
Jan
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next reply other threads:[~2007-01-02 13:08 UTC|newest]
Thread overview: 9+ messages / expand[flat|nested] mbox.gz Atom feed top
2007-01-02 13:08 Jan Kiszka [this message]
2007-01-03 17:52 ` d80211: How does TX flow control work? Jiri Benc
2007-01-03 18:10 ` Jan Kiszka
2007-01-03 18:18 ` Jiri Benc
2007-01-03 18:50 ` Jan Kiszka
2007-01-07 0:00 ` Jan Kiszka
2007-01-08 20:18 ` Jan Kiszka
2007-01-10 18:20 ` Jiri Benc
2007-01-10 18:29 ` Simon Barber
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