From: Bastian Bloessl <basti@b-bl.de>
To: David Miller <davem@davemloft.net>
Cc: netdev@vger.kernel.org, jarkao2@gmail.com
Subject: Re: [PATCH 5/9]: sch_netem: Use requeue list instead of ops->requeue()
Date: Tue, 19 Aug 2008 19:36:09 +0200 [thread overview]
Message-ID: <48AB0489.8060107@b-bl.de> (raw)
In-Reply-To: <20080818.013702.111675433.davem@davemloft.net>
David Miller wrote:
> sch_netem: Use requeue list instead of ops->requeue()
>
> This code just wants to make this packet the "front" one, and that's
> just as simply done by queueing to the ->requeue list.
>
Hi,
I think that might make some difference.
Suppose we have an upper qdisc that dequeues from netem and
puts the packet in it's requeue-list. But after that another
packet could arrive that should be send earlier (delay
distribution, reordering).
As far as I understand it the requeued packet would now
be send before the other.
> --- a/net/sched/sch_netem.c
> +++ b/net/sched/sch_netem.c
> @@ -233,7 +233,8 @@ static int netem_enqueue(struct sk_buff *skb, struct Qdisc *sch)
> */
> cb->time_to_send = psched_get_time();
> q->counter = 0;
> - ret = q->qdisc->ops->requeue(skb, q->qdisc);
> + __skb_queue_tail(&q->qdisc->requeue, skb);
I think this should be __skb_queue_head() because in it's
requeue-list netem has packets that it doesn't want to send yet. So
their time_to_send is likely to be in the future. But reordered
packets have current time as time_to_send.
Or did I get it wrong?
Regards
Bastian Bloessl
prev parent reply other threads:[~2008-08-19 17:59 UTC|newest]
Thread overview: 2+ messages / expand[flat|nested] mbox.gz Atom feed top
2008-08-18 8:37 [PATCH 5/9]: sch_netem: Use requeue list instead of ops->requeue() David Miller
2008-08-19 17:36 ` Bastian Bloessl [this message]
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