From mboxrd@z Thu Jan  1 00:00:00 1970
From: Kevin Wilson <wkevils@gmail.com>
Subject: ntohs() and htons() usgae in the network stack
Date: Wed, 10 Jun 2009 17:08:12 +0300
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Hello,
I will appreciate if someone can explain this mystery to me:

While debugging some kernel module, I added printing of ports.
I had printer both ntohs() and htons() of a port number. I got the same
values. Since I used low port number, I decided to find out from which
port there begins to be a difference. So I tried to write in a simple
kernel module this loop, which tests all ports up till 65536 (since
port number is 16 bit wide):
	...
	int i;
	for (i=0;i<65536;i++)
	 if (ntohs(i) != htons(i))
		printk("found inequality: ntohs(i) != htons(i)\n");

And when running it it did **not** find such a port where ntohs(i) !=
htons ( "found inequality:.. was **not** printed).

So I wondered : when is ntohs(i) != htons(i) ?
Are they always equal (I doubt it); or am I missing something silly here?

I am testing it on x86_64 Intel machine (little endian).
Rgs,
Kevin