Re: linux kernel's IPV6_MULTICAST_HOPS default is 64; should be 1?

[enh <enh@google.com>]

On Mon, May 3, 2010 at 23:22, David Miller <davem@davemloft.net> wrote:
> From: enh <enh@google.com>
> Date: Mon, 3 May 2010 23:19:22 -0700
>
>> for the *unicast* hops, a part of the RFC i didn't quote says:
>>
>>    If the [IPV6_UNICAST_HOPS] option is not set, the
>>    system selects a default value.
>>
>> but for the *multicast* hops, which is what i'm talking about, this
>> part of the quoted text seems pretty definitive:
>>
>>            If IPV6_MULTICAST_HOPS is not set, the default is 1
>>            (same as IPv4 today)
>>
>> this is what my test shows isn't true of linux; linux reuses its
>> unicast default instead.
>
> Ok, I see, so yeah this needs to be fixed to use "1" instead of
> "-1" in the np->xxx ipv6 socket initialization.

i think so. there's already the IPV6_DEFAULT_MCASTHOPS constant
defined to 1 but unused according to gitweb, so you might want to
either use it or remove it.

thanks!

-- 
Elliott Hughes - http://who/enh - http://jessies.org/~enh/