From: Alok Shukla <alokshukla@yahoo.com>
To: netfilter@lists.netfilter.org
Cc: Antony Stone <Antony@Soft-Solutions.co.uk>
Subject: Re: HELP : How to group IP addresses by refering to them as a single name ?
Date: Thu, 19 Sep 2002 11:00:21 -0700 (PDT) [thread overview]
Message-ID: <20020919180021.80821.qmail@web40206.mail.yahoo.com> (raw)
In-Reply-To: <200209191302.g8JD20v19671@vulcan.rissington.net>
Let me say if i am able to sort out the lab in the
accordance that i start my ip settings of lab2
like 192.168.9.1-63 for lab 1
and next 64 for lab 2 , would that help and how ?
but i still think that it still bounds me ..
But i would request you to explain in detail as you
said
Alok SHukla
--- Antony Stone <Antony@Soft-Solutions.co.uk> wrote:
> On Thursday 19 September 2002 8:45 am, Alok Shukla
> wrote:
>
> > HI,
> >
> > I run a College Laboratory with two rooms for the
> > whole labaratory
> > I have given a static IP for each of the computers
> > from 192.168.0.1 to 192.168.0.254.
> >
> > 1. My Lab 1 has IP from 192.198.0.11 to
> 192.168.0.50
> > and Lab 2 has IP from 192.168.0.51 to 192.168.0.90
> >
> > I want to have a set of rules so that i can group
> Lab
> > 1 computers in one group and Lab 2 computers in
> > another group. In this I want to able to shutdown
> the
> > Internet facility by stopping its masquerading as
> a
> > whole by refering as a single name.
> >
> > Like something like :-
> >
> > iptables -t nat -D POSTROUTING -s "LAB1" -d any/0
> -J
> > MASQUERADE
>
> You can't use names like this in rules, however you
> might be able to achieve
> something almost as effective by creating two
> user-defined chains forthe two
> groups of machines, and then putting your rules to
> apply to each group in the
> appropriate chain ?
>
> It's a pity your two groups do not split on a neat
> IP address boundary (maybe
> you could fix this sometime in the future, for
> example by putting all LAB1
> machines in the range 192.168.0.0-63, all LAB2
> machines in the range
> 192.168.0.64-127, and all 'general net admin'
> machines (DNS, NT server etc)
> above 192.168.0.128 ?), however you could try
> splitting them up as follows:
>
> # create a user-defined chain called LAB1
> iptables -N LAB1
> # add rules to match machines *not* in LAB1 and
> return immediately
> iptables -A LAB1 -s 192.168.0.64/26 -j RETURN
> iptables -A LAB1 -s 192.168.0.56/29 -j RETURN
> iptables -A LAB1 -s 192.168.0.52/30 -j RETURN
> iptables -A LAB1 -s 192.168.0.50/31 -j RETURN
> # now any further rules we put in chain LAB1 will
> only apply to those machines
>
> # create user-defined LAB2 chain
> iptables -N LAB2
> # add some rules to eliminate non-LAB2 machines
> iptables -A LAB2 -s 192.168.0.0/27 -j RETURN
> iptables -A LAB2 -s 192.168.0.32/28 -j RETURN
> iptables -A LAB2 -s 192.168.0.48/31 -j RETURN
> # now any further rules we put in chain LAB2 will
> only apply to those machines
>
> I suggest using these chains as follows:
>
> 1. Add rules as necessary to the above chains to
> ACCEPT the traffic you want
> 2. Put a rule at the end of both LAB1 and LAB2
> chains to DROP any other
> traffic
> 3. Call both rules near the start of your FORWARD
> chain and then add any
> other rules for non-(LAB1 or LAB2) machines:
>
> iptables -A FORWARD -m state --state
> ESTABLISHED,RELATED -j ACCEPT
> iptables -A FORWARD -j LAB1
> iptables -A FORWARD -j LAB2
> iptables -A FORWARD -s $extDNS -p tcp --dport 53 -j
> ACCEPT
> iptables -A FORWARD -s $extDNS -p udp --dport 53 -j
> ACCEPT
>
> This would allow servers not in the LAB1 or LAB2
> ranges to access an external
> DNS server, for example.
>
> If you want any help understanding how I created the
> range matches in the two
> chains above, let me know and I'll explain in more
> detail.
>
> Hopw this helps,
>
> Antony.
>
> --
>
> This is not a rehearsal.
> This is Real Life.
>
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next prev parent reply other threads:[~2002-09-19 18:00 UTC|newest]
Thread overview: 10+ messages / expand[flat|nested] mbox.gz Atom feed top
[not found] <200209041320.g84DKjv31137@vulcan.rissington.net>
2002-09-19 7:45 ` HELP : How to group IP addresses by refering to them as a single name ? Alok Shukla
2002-09-19 9:37 ` Rohan Almeida
2002-09-19 13:01 ` Antony Stone
2002-09-19 18:00 ` Alok Shukla [this message]
2002-09-19 19:33 ` Antony Stone
2002-09-20 2:55 ` Joel Newkirk
2002-09-20 12:43 ` Alok Shukla
2002-09-20 13:11 ` Antony Stone
2002-09-21 5:34 ` Darrell A. Escola
2002-09-21 8:01 ` Antony Stone
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