From mboxrd@z Thu Jan 1 00:00:00 1970 From: Antonio Di Bacco Subject: Routing through PtP and iptables Date: Fri, 12 May 2006 23:35:10 +0200 Message-ID: <200605122335.10078.antonio.dibacco@aruba.it> Mime-Version: 1.0 Content-Transfer-Encoding: quoted-printable Return-path: Content-Disposition: inline List-Id: List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Sender: netfilter-bounces@lists.netfilter.org Errors-To: netfilter-bounces@lists.netfilter.org Content-Type: text/plain; charset="iso-8859-1" To: netfilter@lists.netfilter.org Hi all, I have two identical linux boxes (A e B), each one with two interfaces: an= =20 ethernet (eth0 with ip 192.168.1.50) and an hdlc (hdlc0). The two boxes are= =20 only connected via a link through their hdlc interfaces. Because they have = to=20 be =A0exactly the same, if I have to assign an ip address to hdlc0 of A the= n=20 the hdlc0 of B should have the same ip address. Each one should have a=20 default route that cannot coincide with the hdlc interface. Every linux box= =20 has a web server. When I connect with my notebook to box A I want to reach= =20 the web server on A typing in my browser http://192.168.1.50 and I want to= =20 reach web server on B typing http://192.168.1.50:8080 . Some one knows how could it be possible? Thank you for your help, Antonio.