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From: Rohit Kumar Mehta <rohitm@engr.uconn.edu>
To: netfilter@lists.netfilter.org
Subject: simple port forwarding question
Date: Mon, 03 Nov 2003 08:58:53 -0500	[thread overview]
Message-ID: <3FA65F1D.20205@engr.uconn.edu> (raw)


Hi guys, I was wondering if someone could help me out here.  I am fairly 
well confused after trying to muddle through
this tutorial:
http://iptables-tutorial.frozentux.net/iptables-tutorial.html

I think what I want to do should be easy.  Perhaps someone could help.

We are trying to trick the systems into believing that the Kerberos 5 
server is on IP#2 (let's call it 192.168.28.3)
but it is in fact on IP#1 (192.168.28.2).

Maybe my attempted iptables commands will make it blatantly obvious what 
I am trying to do:

iptables -t nat -A PREROUTING --dst 192.168.28.3 -p tcp --dport 88 -j 
DNAT --to 192.168.28.2
iptables -t nat -A PREROUTING --dst 192.168.28.3 -p udp --dport 88 -j 
DNAT --to 192.168.28.2

iptables -t nat -A POSTROUTING -p udp --dst 192.168.28.2 --dport 88 -j 
SNAT --to-source 192.168.28.3
iptables -t nat -A POSTROUTING -p tcp --dst 192.168.28.2 --dport 88 -j 
SNAT --to-source 192.168.28.3

iptables -t nat -A OUTPUT --dst 192.168.28.3 -p tcp --dport 88 -j DNAT 
--to-destination 192.168.28.2
iptables -t nat -A OUTPUT --dst 192.168.28.3 -p udp --dport 88 -j DNAT 
--to-destination 192.168.28.2


Basically we want it so that if I do a "telnet 192.168.28.3 88", I get a 
connection to "192.168.28.2:88"
This works - when I initiate the connection from 192.168.28.3, but from 
any other machine on the network
it does not work.

Am I doing something wrong or forgetting a key step?  Thanks!

Rohit



             reply	other threads:[~2003-11-03 13:58 UTC|newest]

Thread overview: 5+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2003-11-03 13:58 Rohit Kumar Mehta [this message]
2003-11-03 11:57 ` simple port forwarding question Herman
2003-11-03 14:07 ` SBlaze
2003-11-03 14:12   ` Rohit Kumar Mehta
  -- strict thread matches above, loose matches on Subject: below --
2003-11-03 18:04 Han, Yan

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