From: Saul Wold <sgw@linux.intel.com>
To: Patches and discussions about the oe-core layer
<openembedded-core@lists.openembedded.org>
Subject: Re: [PATCH 1/2] license.py: fix behaviour of copyleft_compliance
Date: Wed, 04 Apr 2012 09:54:51 -0700 [thread overview]
Message-ID: <4F7C7CDB.1070205@linux.intel.com> (raw)
In-Reply-To: <1333399030-28619-1-git-send-email-eric@eukrea.com>
On 04/02/2012 01:37 PM, Eric Bénard wrote:
> actually if a package has a license in its LICENSE variable
> which is not in the whitelist nor in the blacklist and even
> if an other license in this variable is in the whitelist,
> the package gets excluded and is not taken in account in the
> copyleft_compliance.
> This patch solves this by excluding a recipe _only_ if the
> LICENSE variable includes a pattern from the blacklist and
> including a recipe only if it includes a variable from the
> whitelist _and_ none from the blacklist.
>
> Example in busybox which has LICENSE="GPLv2& BSD-4-Clause",
> with the actual behaviour (where he blacklist contains only
> CLOSED Proprietary) we get :
> DEBUG: copyleft: busybox-1.19.4 is excluded: recipe has excluded licenses: BSD-4-Clause
> which is not sane because busybox is covered by a copyleft license
> which is GPLv2 and should match the default whitelist which is
> GPL* LGPL*.
>
> Signed-off-by: Eric Bénard<eric@eukrea.com>
> ---
> v2: updated and tested after Kergoth's review on IRC
>
> meta/lib/oe/license.py | 11 +++++++----
> 1 files changed, 7 insertions(+), 4 deletions(-)
>
> diff --git a/meta/lib/oe/license.py b/meta/lib/oe/license.py
> index 5914506..173e319 100644
> --- a/meta/lib/oe/license.py
> +++ b/meta/lib/oe/license.py
> @@ -86,8 +86,10 @@ def is_included(licensestr, whitelist=None, blacklist=None):
> """
>
> def include_license(license):
> - return (any(fnmatch(license, pattern) for pattern in whitelist) and not
> - any(fnmatch(license, pattern) for pattern in blacklist))
> + return any(fnmatch(license, pattern) for pattern in whitelist)
> +
> + def exclude_license(license):
> + return any(fnmatch(license, pattern) for pattern in blacklist)
>
> def choose_licenses(alpha, beta):
> """Select the option in an OR which is the 'best' (has the most
> @@ -106,8 +108,9 @@ def is_included(licensestr, whitelist=None, blacklist=None):
> blacklist = []
>
> licenses = flattened_licenses(licensestr, choose_licenses)
> - excluded = filter(lambda lic: not include_license(lic), licenses)
> + excluded = filter(lambda lic: exclude_license(lic), licenses)
> + included = filter(lambda lic: include_license(lic), licenses)
> if excluded:
> return False, excluded
> else:
> - return True, None
> + return True, included
Merged both of these into OE-Core
Thanks
Sau!
prev parent reply other threads:[~2012-04-04 17:04 UTC|newest]
Thread overview: 3+ messages / expand[flat|nested] mbox.gz Atom feed top
2012-04-02 20:37 [PATCH 1/2] license.py: fix behaviour of copyleft_compliance Eric Bénard
2012-04-02 20:37 ` [PATCH 2/2] copyleft_compliance: also print the reason for including a package Eric Bénard
2012-04-04 16:54 ` Saul Wold [this message]
Reply instructions:
You may reply publicly to this message via plain-text email
using any one of the following methods:
* Save the following mbox file, import it into your mail client,
and reply-to-all from there: mbox
Avoid top-posting and favor interleaved quoting:
https://en.wikipedia.org/wiki/Posting_style#Interleaved_style
* Reply using the --to, --cc, and --in-reply-to
switches of git-send-email(1):
git send-email \
--in-reply-to=4F7C7CDB.1070205@linux.intel.com \
--to=sgw@linux.intel.com \
--cc=openembedded-core@lists.openembedded.org \
/path/to/YOUR_REPLY
https://kernel.org/pub/software/scm/git/docs/git-send-email.html
* If your mail client supports setting the In-Reply-To header
via mailto: links, try the mailto: link
Be sure your reply has a Subject: header at the top and a blank line
before the message body.
This is a public inbox, see mirroring instructions
for how to clone and mirror all data and code used for this inbox