[OpenRISC] [PATCH 13/21] arch: don't memset(0) memory returned by memblock_alloc()

Geert Uytterhoeven
2019-01-16T14:17:22Z

On Wed, Jan 16, 2019 at 2:45 PM Mike Rapoport <rppt@linux.ibm.com> wrote:
> memblock_alloc() already clears the allocated memory, no point in doing it
> twice.
>
> Signed-off-by: Mike Rapoport <rppt@linux.ibm.com>

> arch/m68k/mm/mcfmmu.c | 1 -

For m68k part:
Acked-by: Geert Uytterhoeven <geert@linux-m68k.org>

> --- a/arch/m68k/mm/mcfmmu.c
> +++ b/arch/m68k/mm/mcfmmu.c
> @@ -44,7 +44,6 @@ void __init paging_init(void)
> int i;
>
> empty_zero_page = (void *) memblock_alloc(PAGE_SIZE, PAGE_SIZE);
> - memset((void *) empty_zero_page, 0, PAGE_SIZE);
>
> pg_dir = swapper_pg_dir;
> memset(swapper_pg_dir, 0, sizeof(swapper_pg_dir));

Gr{oetje,eeting}s,

Geert

--
Geert Uytterhoeven -- There's lots of Linux beyond ia32 -- geert at linux-m68k.org

In personal conversations with technical people, I call myself a hacker. But
when I'm talking to journalists I just say "programmer" or something like that.
-- Linus Torvalds