[PULL 03/14] hw/block/nvme: Simplify timestamp sum

[Laurent Vivier <laurent@vivier.eu>]

From: Philippe Mathieu-Daudé <philmd@redhat.com>

As the 'timestamp' variable is declared as a 48-bit bitfield,
we do not need to wrap the sum result.

Signed-off-by: Philippe Mathieu-Daudé <philmd@redhat.com>
Reviewed-by: Klaus Jensen <k.jensen@samsung.com>
Message-Id: <20201002075716.1657849-1-philmd@redhat.com>
Signed-off-by: Laurent Vivier <laurent@vivier.eu>
---
 hw/block/nvme.c | 7 +------
 1 file changed, 1 insertion(+), 6 deletions(-)

diff --git a/hw/block/nvme.c b/hw/block/nvme.c
index 63078f600920..44fa5b90769b 100644
--- a/hw/block/nvme.c
+++ b/hw/block/nvme.c
@@ -1280,12 +1280,7 @@ static inline uint64_t nvme_get_timestamp(const NvmeCtrl *n)
 
     union nvme_timestamp ts;
     ts.all = 0;
-
-    /*
-     * If the sum of the Timestamp value set by the host and the elapsed
-     * time exceeds 2^48, the value returned should be reduced modulo 2^48.
-     */
-    ts.timestamp = (n->host_timestamp + elapsed_time) & 0xffffffffffff;
+    ts.timestamp = n->host_timestamp + elapsed_time;
 
     /* If the host timestamp is non-zero, set the timestamp origin */
     ts.origin = n->host_timestamp ? 0x01 : 0x00;
-- 
2.26.2