From: Paolo Bonzini <pbonzini@redhat.com>
To: "Philippe Mathieu-Daudé" <philmd@redhat.com>,
"P J P" <ppandit@redhat.com>
Cc: Fam Zheng <fam@euphon.net>, Marcelo Tosatti <mtosatti@redhat.com>,
Mark Cave-Ayland <mark.cave-ayland@ilande.co.uk>,
QEMU Developers <qemu-devel@nongnu.org>,
Bugs SysSec <bugs-syssec@rub.de>,
Stefano Garzarella <sgarzare@redhat.com>
Subject: Re: [Qemu-devel] [PATCH v3 1/2] scsi: lsi: exit infinite loop while executing script (CVE-2019-12068)
Date: Tue, 13 Aug 2019 16:33:21 +0200 [thread overview]
Message-ID: <3a48e557-985d-7274-81d9-fe963f74e59a@redhat.com> (raw)
In-Reply-To: <b2944559-264e-cb48-8a04-4f238197f835@redhat.com>
On 13/08/19 12:31, Philippe Mathieu-Daudé wrote:
>> |
>> | s->istat1 |= LSI_ISTAT1_SRUN;
>> | again:
>> | - insn_processed++;
>> | + if (++insn_processed > LSI_MAX_INSN) {
>> | + trace_lsi_execute_script_tc_illegal();
>> | + lsi_script_dma_interrupt(s, LSI_DSTAT_IID);
>> | + lsi_disconnect(s);
>> | + trace_lsi_execute_script_stop();
>> | + return;
> My understanding of Marcelo's explanation
> (https://lists.gnu.org/archive/html/qemu-devel/2019-08/msg01427.html) is
> we can kill insn_processed.
>
All zeros is not an illegal instruction, it's just a block move with
zero transfer count. It's not clear to me from the spec that the
behavior of QEMU, skipping the second word, is correct, but I do not
really dare changing it.
After the first instruction is processed, "again" is only reached if
s->waiting == LSI_NOWAIT. Therefore, we could move the Windows hack to
the beginning and remove the s->waiting condition. The only change
would be that it would also be triggered by all zero instructions, like this:
diff --git a/hw/scsi/lsi53c895a.c b/hw/scsi/lsi53c895a.c
index 10468c1..9d714af 100644
--- a/hw/scsi/lsi53c895a.c
+++ b/hw/scsi/lsi53c895a.c
@@ -185,6 +185,9 @@ static const char *names[] = {
/* Flag set if this is a tagged command. */
#define LSI_TAG_VALID (1 << 16)
+/* Maximum instructions to process. */
+#define LSI_MAX_INSN 10000
+
typedef struct lsi_request {
SCSIRequest *req;
uint32_t tag;
@@ -1132,7 +1135,19 @@ static void lsi_execute_script(LSIState *s)
s->istat1 |= LSI_ISTAT1_SRUN;
again:
- insn_processed++;
+ if (++insn_processed > LSI_MAX_INSN) {
+ /* Some windows drivers make the device spin waiting for a memory
+ location to change. If we have been executed a lot of code then
+ assume this is the case and force an unexpected device disconnect.
+ This is apparently sufficient to beat the drivers into submission.
+ */
+ if (!(s->sien0 & LSI_SIST0_UDC)) {
+ qemu_log_mask(LOG_GUEST_ERROR,
+ "lsi_scsi: inf. loop with UDC masked");
+ }
+ lsi_script_scsi_interrupt(s, LSI_SIST0_UDC, 0);
+ lsi_disconnect(s);
+ }
insn = read_dword(s, s->dsp);
if (!insn) {
/* If we receive an empty opcode increment the DSP by 4 bytes
@@ -1569,19 +1584,7 @@ again:
}
}
}
- if (insn_processed > 10000 && s->waiting == LSI_NOWAIT) {
- /* Some windows drivers make the device spin waiting for a memory
- location to change. If we have been executed a lot of code then
- assume this is the case and force an unexpected device disconnect.
- This is apparently sufficient to beat the drivers into submission.
- */
- if (!(s->sien0 & LSI_SIST0_UDC)) {
- qemu_log_mask(LOG_GUEST_ERROR,
- "lsi_scsi: inf. loop with UDC masked");
- }
- lsi_script_scsi_interrupt(s, LSI_SIST0_UDC, 0);
- lsi_disconnect(s);
- } else if (s->istat1 & LSI_ISTAT1_SRUN && s->waiting == LSI_NOWAIT) {
+ if (s->istat1 & LSI_ISTAT1_SRUN && s->waiting == LSI_NOWAIT) {
if (s->dcntl & LSI_DCNTL_SSM) {
lsi_script_dma_interrupt(s, LSI_DSTAT_SSI);
} else {
@@ -1969,6 +1972,10 @@ static void lsi_reg_writeb(LSIState *s, int offset, uint8_t val)
case 0x2f: /* DSP[24:31] */
s->dsp &= 0x00ffffff;
s->dsp |= val << 24;
+ /*
+ * FIXME: if s->waiting != LSI_NOWAIT, this will only execute one
+ * instruction. Is this correct?
+ */
if ((s->dmode & LSI_DMODE_MAN) == 0
&& (s->istat1 & LSI_ISTAT1_SRUN) == 0)
lsi_execute_script(s);
@@ -1987,6 +1994,10 @@ static void lsi_reg_writeb(LSIState *s, int offset, uint8_t val)
break;
case 0x3b: /* DCNTL */
s->dcntl = val & ~(LSI_DCNTL_PFF | LSI_DCNTL_STD);
+ /*
+ * FIXME: if s->waiting != LSI_NOWAIT, this will only execute one
+ * instruction. Is this correct?
+ */
if ((val & LSI_DCNTL_STD) && (s->istat1 & LSI_ISTAT1_SRUN) == 0)
lsi_execute_script(s);
break;
Does it make sense? Do you have a reproducer, and does the above
patch work? Also, can the reproducer be modified into a qtest test
case?
Thanks,
Paolo
next prev parent reply other threads:[~2019-08-13 14:34 UTC|newest]
Thread overview: 9+ messages / expand[flat|nested] mbox.gz Atom feed top
2019-08-09 6:38 [Qemu-devel] [PATCH v3 0/2] scsi: lsi: break infinite loop after 10k instructions P J P
2019-08-09 6:38 ` [Qemu-devel] [PATCH v3 1/2] scsi: lsi: exit infinite loop while executing script (CVE-2019-12068) P J P
2019-08-13 10:05 ` P J P
2019-08-13 10:31 ` Philippe Mathieu-Daudé
2019-08-13 14:33 ` Paolo Bonzini [this message]
2019-08-14 10:25 ` P J P
2019-08-14 10:38 ` Paolo Bonzini
2019-08-14 12:08 ` P J P
2019-08-09 6:38 ` [Qemu-devel] [PATCH v3 2/2] scsi: lsi: use macro LSI_MAX_INSN instead of a magic number P J P
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