From: Avi Kivity <avi@redhat.com>
To: grisu46 <grisu46@yahoo.it>
Cc: qemu-devel@nongnu.org
Subject: Re: [Qemu-devel] How does a system call work on QEMU?
Date: Thu, 14 May 2009 20:48:53 +0300 [thread overview]
Message-ID: <4A0C5985.6020206@redhat.com> (raw)
In-Reply-To: <4A0C50D4.9020803@yahoo.it>
grisu46 wrote:
>> No. Look at target-i386/translate.c, case 0x105 for syscall
>> emulation. Eventually it ends up calling helper_syscall().
>>
>
> Simplify?
> I am a newbie.
Sorry, you're on your own. I can give you pointers but it's up to you
to follow them. If you're serious about understanding qemu you should
be prepared a lot of time reading the source code and processor
documentation.
--
I have a truly marvellous patch that fixes the bug which this
signature is too narrow to contain.
next prev parent reply other threads:[~2009-05-14 17:49 UTC|newest]
Thread overview: 15+ messages / expand[flat|nested] mbox.gz Atom feed top
2009-05-14 6:50 [Qemu-devel] How does a system call work on QEMU? helicoterus-elih
2009-05-14 10:19 ` Paul Brook
2009-05-14 13:10 ` Heli
2009-05-14 16:40 ` Avi Kivity
2009-05-14 17:11 ` grisu46
2009-05-14 17:48 ` Avi Kivity [this message]
2009-05-14 18:00 ` grisu46
2009-05-15 4:49 ` Glauber Costa
2009-05-17 8:46 ` Heli
2009-05-17 9:31 ` Avi Kivity
2009-05-17 14:41 ` Fernando Carrijo
2009-05-14 14:57 ` Mulyadi Santosa
-- strict thread matches above, loose matches on Subject: below --
2009-05-15 8:54 helicoterus-elih
2009-05-13 18:41 helicoterus-elih
2009-05-14 4:38 ` Mulyadi Santosa
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