From: "Alex Bennée" <alex.bennee@linaro.org>
To: Rafael Kioji <rafaelkioji@gmail.com>
Cc: qemu-devel@nongnu.org
Subject: Re: [Qemu-devel] Translation block identification.
Date: Tue, 01 May 2018 11:43:25 +0100 [thread overview]
Message-ID: <87sh7bac6q.fsf@linaro.org> (raw)
In-Reply-To: <8f27190a-3875-2eea-4138-172e590f4eb2@gmail.com>
Rafael Kioji <rafaelkioji@gmail.com> writes:
> This logging flag prints what I want. But I really wanted is to get
> this info inside the QEMU source code. Why am I not able to lookup the
> symbols in the translator.c file the way I showed?
Without a failing patch it's hard to say, after all the working
disassembly is called at the bottom of translator_loop():
ops->disas_log(db, cpu);
>
> Kind regards,
> Rafael
>
> On 5/1/2018 6:04 PM, Alex Bennée wrote:
>> Rafael Kioji <rafaelkioji@gmail.com> writes:
>>
>>> Dear all,
>>>
>>> During translation how can I identify what is the basic block of the
>>> guest code? I wanted to know whether the block being translated is the
>>> beginning of a function and get its name.
>>>
>>> My current approach involves looking up the symbol associated with the
>>> first PC of the translation block. But no symbol is ever found. What I
>>> did was to add the following code in the function "translator_loop" at
>>> "accel/tcg/translator.c":
>>>
>>> printf("sym: %lu %s\n", tb->pc, lookup_symbol(tb->pc));
>>>
>>> The function lookup_symbol is defined in the file "./disas.c". I am
>>> compiling my application with symbols (-g). My target arch is ARM.
>> If you run QEMU with the debug flags you should see name resolution for
>> each basic block. e.g.
>>
>> qemu-arm -d in_asm prog
>>
>> --
>> Alex Bennée
--
Alex Bennée
prev parent reply other threads:[~2018-05-01 10:43 UTC|newest]
Thread overview: 6+ messages / expand[flat|nested] mbox.gz Atom feed top
2018-05-01 9:28 [Qemu-devel] Translation block identification Rafael Kioji
2018-05-01 10:04 ` Alex Bennée
2018-05-01 10:20 ` Rafael Kioji
2018-05-01 10:28 ` Peter Maydell
2018-05-01 10:47 ` Rafael Kioji
2018-05-01 10:43 ` Alex Bennée [this message]
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