[Qemu-devel] Re: target-sparc/TODO

[Blue Swirl <blauwirbel@gmail.com>]

On Fri, Aug 21, 2009 at 3:40 PM, Artyom
Tarasenko<atar4qemu@googlemail.com> wrote:
> 2009/8/21 Artyom Tarasenko <atar4qemu@googlemail.com>:
>> 2009/8/20 Blue Swirl <blauwirbel@gmail.com>:
>>> On Thu, Aug 20, 2009 at 12:44 PM, Artyom
>>> Tarasenko<atar4qemu@googlemail.com> wrote:
>>>>>> Particularly I'm interested if
>>>>>>
>>>>>> jmp     %l1, %g4, %g0
>>>>>>
>>>>>> may behave other than on a real hw.
>>>>>
>>>>> No, if rd is %g0, the current PC will not be written anywhere (not by
>>>>> real HW either).
>>>>
>>>> The reason I asked is the two following pieces of code work
>>>> differently on a real and emulated SS-5. On a real one spacel! does an
>>>> asi write, and spacel@ does an asi read, and under qemu  spacel! seems
>>>> to do nothing, and spacel@ returns its second parameter multiplied by
>>>> 4. Both of them don't even try to call an [unimplemented] asi
>>>> operation, I've runned the tests with mmu and asi debug turned on.
>>>>
>>>> Real SS-5:
>>>>
>>>> ok 0 0 spacel@ .
>>>> Data Access Error
>>>> ok 0 20 spacel@ .
>>>> 0
>>>> ok 12345678 0 20 spacel!
>>>> ok 0 20 spacel@ .
>>>> 12345678
>>>> ok
>>>>
>>>>
>>>> qemu SS-5:
>>>>
>>>> ok 0 0 spacel@ .
>>>> 0
>>>> ok 0 20 spacel@ .
>>>> 80
>>>> ok 12345678 0 20 spacel!
>>>> ok 0 20 spacel@ .
>>>> 80
>>>> ok
>>>>
>>>> I don't know sparc asm good enogh, but qemu behavior seems to be
>>>> logical: in the first case I see no store op, and there are shifts
>>>> which would multiply by 4:
>>>>
>>>> ok see spacel!
>>>> code spacel!
>>>> ffd26e0c     ld      [%g7], %l2
>>>> ffd26e10     add     %g7, 4, %g7
>>>> ffd26e14     ld      [%g7], %l0
>>>> ffd26e18     add     %g7, 4, %g7
>>>> ffd26e1c     sll     %g4, 2, %g4
>>>> ffd26e20     call    ffd26e24
>>>> ffd26e24     add     %g0, 14, %l1
>>>>
>>>> ok ffd26e24 dis
>>>> ffd26e24     add     %g0, 14, %l1
>>>> ffd26e28     add     %o7, %l1, %l1
>>>> ffd26e2c     jmp     %l1, %g4, %g0
>>>> ffd26e30     ba      ffd26f68
>>>> ok
>>>>
>>>> ok see spacel@
>>>> code spacel@
>>>> ffd26830     ld      [%g7], %l0
>>>> ffd26834     add     %g7, 4, %g7
>>>> ffd26838     sll     %g4, 2, %g4
>>>> ffd2683c     call    ffd26840
>>>> ffd26840     add     %g0, 14, %l1
>>>>
>>>> ok ffd26840 dis
>>>> ffd26840     add     %g0, 14, %l1
>>>> ffd26844     add     %o7, %l1, %l1
>>>> ffd26848     jmp     %l1, %g4, %g0
>>>> ffd2684c     ba      ffd26984
>>>>
>>>>
>>>> The code is identical on a real and emulated SS.
>>>>
>>>> It must be the jump, which jumps differently on a real hw and under
>>>> qemu. Do you see from the code where the jump would jump to, or maybe
>>>> you have a suggestion how to check where the jump jumps to on the real
>>>> hw?
>>>
>>> The target of the call instruction is also a delay slot instruction
>>> for the call itself. Maybe this case is not handled correctly?
>>
>> Good idea! Don't know how to test it though.
>>
>> And what about "ba" in the delay slot of "jmp"? Is the correct
>> behavior described somewhere? Would jump just be ignored? Whould it
>> execute one instruction on jump destination and then branch? Would
>> branch be ignored?
>
> Page 55 of The SPARC v8 Architecture Manual
> (http://www.sparc.org/standards/V8.pdf) describes this case
> explicitly:
> cpu should execute one instruction on the jump target and then branch.
>  Is it what qemu currently does?

I may be blind, I don't see the description of this case in that page.
However, I made a small Linux test program to test it:
    .global _start
    .type _start, function
_start:
    mov 1, %o0
    call 1f
#ifdef NOP
    nop
#endif
1:   inc %o0
    mov 1, %g1
    ta 0x10

(and a BSD version:
#include <sys/syscall.h>

    .globl _start
_start:
    mov 1, %o0
    call 1f
#ifdef NOP
    nop
#endif
1:   inc %o0
    mov SYS_exit, %g1
    ta 0
)

Both QEMU and real (Sparc64) hardware exit with return value of 3, so
the inc is re-executed. If I add a nop in the call delay slot, the
return value is 2.