From: "andrzej zaborowski" <balrog@zabor.org>
To: todd@fries.net, qemu-devel@nongnu.org
Subject: Re: [Qemu-devel] Patch: cpu-all.h for better cycle counter
Date: Mon, 26 Mar 2007 00:07:16 +0200 [thread overview]
Message-ID: <fb249edb0703251507q6085d6dfi13340ecf15693f78@mail.gmail.com> (raw)
In-Reply-To: <20070321023726.GA11696@fries.net>
Hi,
On 21/03/07, Todd T. Fries <todd@fries.net> wrote:
> This is relative to the 20070319 snapshot.
>
> --- cpu-all.h.orig Fri Mar 16 18:58:11 2007
> +++ cpu-all.h Tue Mar 20 21:14:10 2007
> @@ -1012,13 +1012,22 @@ static inline int64_t cpu_get_real_ticks
> #endif
> }
> #else
> -/* The host CPU doesn't have an easily accessible cycle counter.
> - Just return a monotonically increasing vlue. This will be totally wrong,
> - but hopefully better than nothing. */
> +# warning non-optimized CPU
> +#include <sys/time.h>
> +#include <time.h>
> +
> static inline int64_t cpu_get_real_ticks (void)
> {
> - static int64_t ticks = 0;
> - return ticks++;
> + struct timeval tv;
> + static int64_t i = 0;
> + int64_t j;
> +
> + gettimeofday(&tv, NULL);
> + do {
> + j = (tv.tv_sec * (uint64_t) 1000000) + tv.tv_usec;
> + } while (i == j);
> + i = j;
> + return j;
Isn't this an infinite loop? gettimeofday() was left out of the loop.
How about "return j + (ticks++)" instead of the loop? If I understand
correctly it may slow things down to below 1Hz.
> }
> #endif
>
> --
> Todd Fries .. todd@fries.net
>
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> http://todd.fries.net/pgp.txt
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>
>
>
Regards,
Andrew
next prev parent reply other threads:[~2007-03-25 22:09 UTC|newest]
Thread overview: 6+ messages / expand[flat|nested] mbox.gz Atom feed top
2007-03-21 2:37 [Qemu-devel] Patch: cpu-all.h for better cycle counter Todd T. Fries
2007-03-25 22:07 ` andrzej zaborowski [this message]
2007-03-25 22:08 ` andrzej zaborowski
2007-03-26 12:52 ` Marc Lörner
2007-03-26 20:37 ` andrzej zaborowski
2007-03-27 6:33 ` Marc Lörner
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