Re: [PATCH] x86, irq, fix logical AND/OR error in check_irq_vectors_for_cpu_disable()

["Chen, Gong" <gong.chen@linux.intel.com>]

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On Tue, Dec 24, 2013 at 08:19:09AM -0500, Prarit Bhargava wrote:
> On 12/23/2013 09:51 PM, Chen, Gong wrote:
> > On Mon, Dec 23, 2013 at 09:39:12AM -0500, Prarit Bhargava wrote:
> >> diff --git a/arch/x86/kernel/irq.c b/arch/x86/kernel/irq.c
> >> index 7d40698..aed7acc 100644
> >> --- a/arch/x86/kernel/irq.c
> >> +++ b/arch/x86/kernel/irq.c
> >> @@ -281,7 +281,7 @@ int check_irq_vectors_for_cpu_disable(void)
> >>  			desc = irq_to_desc(irq);
> >>  			data = irq_desc_get_irq_data(desc);
> >>  			affinity = data->affinity;
> >> -			if (irq_has_action(irq) || !irqd_is_per_cpu(data) ||
> >> +			if (irq_has_action(irq) && !irqd_is_per_cpu(data) &&
> >>  			    !cpumask_subset(affinity, cpu_online_mask))
> >>  				this_count++;
> > Hi, Prarit
> > 
> > I noticed that you don't mention another question I asked in last mail.
> > 
> > "It looks like cpu_online_mask will be updated until cpu_disable_common
> > is called, but your check_vectors is called before that."
> 
> Oh, I'm sorry ... Yes, check_irq_vectors_for_cpu_disable() is called before we
> remove the CPU from the maps.  If there is an error then we have to do much less
> clean up of the code.  I explicitly take into account the cpu that is being
> downed into the check vectors code.
> 
Here is my question: How to decide this_count can be incrased?
1) it is a valid irq(irq_has_action) 2) it is not percpu irq(!irqd_is_per_cpu)
3) it is not shared with left online cpus(!cpumask_subset)

For item 3, I have some concerns.
Your current codes are called before cpu_disable_common, so affinity and
cpu_online_mask are both not updated. BTW, it means your calculation
for count is not correct because it concludes one to-be-off-lined cpu

+       for_each_online_cpu(cpu) {
+               if (cpu == smp_processor_id())
+                       continue;
+               for (vector = FIRST_EXTERNAL_VECTOR; vector < NR_VECTORS;
+                    vector++) {
+                       if (per_cpu(vector_irq, cpu)[vector] < 0)
+                               count++;
+               }
+       }

Back to my question, assume cpu1 will be off-lined and one irq affinity is
set as (1, 2) -- this irq will be bypassed. Looks good. But if one irq
affinity is set as only (1), -- this irq is bypassed, too. Not right!

Furthermore, you even can't use cpumask_subset as evaluation condition,
whatever affinity/cpu_online_mask is updated or not. Let me paste the
comment of cpumask_subset:
/**
 * cpumask_subset - (*src1p & ~*src2p) == 0
 * @src1p: the first input
 * @src2p: the second input
 *
 * Returns 1 if *@src1p is a subset of *@src2p, else returns 0
 */
Here we can see, even if src1p is an empty set, it still can be considered
as the subset of src2p. For our this special case, I mean cpu1 will
be off-lined and one irq affinity is set as (1). If this irq affinity
is updated to (0), it means no cpu is bound to this irq, but the
calculation of cpumask_subset will return true and this irq will be
bypassed. For this case, cpumask_empty should be more suitable.

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