[U-Boot] [PATCH 4/4] ARM: bcm283x: Switch to generic timer

[Marek Vasut <marex@denx.de>]

On Wednesday, May 06, 2015 at 12:37:38 AM, Stephen Warren wrote:
> On 05/05/2015 04:17 PM, Marek Vasut wrote:
> > On Tuesday, May 05, 2015 at 11:46:56 PM, Stephen Warren wrote:
> >> On 05/04/2015 02:54 PM, Marek Vasut wrote:
> >>> Switch to generic timer implementation from lib/time.c .
> >>> This also fixes a signed overflow which was in __udelay()
> >>> implementation.
> >> 
> >> Can you explain that a bit more?
> >> 
> >>> -void __udelay(unsigned long usec)
> >>> -{
> >>> -	ulong endtime;
> >>> -	signed long diff;
> >>> -
> >>> -	endtime = get_timer_us(0) + usec;
> >>> -
> >>> -	do {
> >>> -		ulong now = get_timer_us(0);
> >>> -		diff = endtime - now;
> >>> -	} while (diff >= 0);
> >>> -}
> >> 
> >> I believe since endtime and now hold micro seconds, there shouldn't be
> >> any overflow so long as the microsecond difference fits into 31 bits,
> >> i.e. so long as usec is less than ~36 minutes. I doubt anything is
> >> calling __udelay() with that large of a value. Perhaps the issue this
> >> patch fixes is in get_timer_us(0) instead, or something else changed as
> >> a side-effect?
> > 
> > The generic implementation caters for full 32-bit range, that's all.
> > Since the argument of this function is unsigned, it can overflow if
> > you use argument which is bigger than 31 bits. OK like that ?
> 
> Sorry, I still don't understand. Both the __udelay() here and in
> lib/time.c take an unsigned long argument. I don't see how switching one
> out for the other can affect anything if the argument type is the issue.

So, if now is close to 0x7fffffff (which it can), then if endtime is big-ish,
diff will become negative and this udelay() will not perform the correct delay,
right ?

> Besides, what's passing a value >~36 minutes to udelay()?

Nothing, but that doesn't mean we can have a possibly broken implementation, 
right ?

Best regards,
Marek Vasut