[U-Boot] ## Application terminated, rc = 0x1

Wolfgang Denk
2015-09-24T05:55:26Z

Dear ba_f,

In message <5c515fb3b2f956768d10d2e2c2e9402e@rbg.informatik.tu-darmstadt.de> you wrote:
>
> But the kernel crushes pretty early with the following u-boot output:
>
> ## Starting application at 0x01000000 ...
> ## Application terminated, rc = 0x1

This is NOT a crash. The program terminates normally with a return
code of 1.

> What may cause "Application terminated, rc = 0x1"?

Something that takes the same effect as "return(1)" from your main()
function, resp. an "exit(1)" from other parts of the code.

> I don't think it is a regular code exit, like main(){ return 1; }.

But yes, it is. From the line

## Application terminated, rc = 0x1

you can see that the program returned normally to U-Boot, and U-Boot
continues running (unless your code destroyed any of the U-Boot
execution environment).

Best regards,

Wolfgang Denk

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