ask some questions about u-boot's bootm command

["poorbeyond" <poorbeyond@163.com>]

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my cpu is 860T, using bootm command boot a linux kernel image, the following message print by smc1:

bootm 300000

## Booting image at 00300000 ...
   Image Name:   Linux-2.6.20.14
   Image Type:   PowerPC Linux Kernel Image (gzip compressed)
   Data Size:    1081591 Bytes =  1 MB
   Load Address: 00100000
   Entry Point:  00100000
   Verifying Checksum ... OK
   Uncompressing Kernel Image ... OK
## Current stack ends at 0x01D5DB10 => set upper limit to 0x00800000
No initrd
## Transferring control to Linux (at address 00100000) ...



then, the program has no response.

i debug it througth BDM, in u-boot function "do_bootm_linux", execute at "kernel = (void (*)(bd_t *, ulong, ulong, ulong, ulong))hdr->ih_ep", the program branch to address "0x00000000", the code is shown as following:
00000000    mr    r31,r3
00000004    mr    r30,r4
00000008    mr    r29,r5
0000000C    mr    r28,r6
00000010    mr    r27,r7
00000014    bl    0x000020C8
00000018    mfmsr    r0
0000001C    ori    r0,r0,0x30
00000020    mtspr    SRR1,r0
00000024    lis    r0,0xC0002004@h
00000028    ori    r0,r0,0xC0002004@l
0000002C    mtspr    SRR0,r0
00000030    rfi


my questions are:

1. Is the code "kernel = (void (*)(bd_t *, ulong, ulong, ulong, ulong))hdr->ih_ep" branch right?

2. What's the expected code after "kernel = (void (*)(bd_t *, ulong, ulong, ulong, ulong))hdr->ih_ep"?

3. When the kernel run to the "boot/simple/head.s"?


thanks a lot





poorbeyond
2007-07-22

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