From: "Wang, Baojun" <wangbj@lzu.edu.cn>
To: linuxppc-dev@ozlabs.org
Subject: Execute user program in kernel mode?
Date: Tue, 30 Oct 2007 19:45:22 +0800 [thread overview]
Message-ID: <393807068.14207@eyou.net> (raw)
Message-ID: <200710301945.25313.wangbj@lzu.edu.cn> (raw)
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hi,
Is it possible to run user program (statically linked) in kernel mode? for
example the user program entry is 0x10000000, can we call it directly from
kernel? I've tried many times, but I got the following Error(Oops):
Oops: Exception in kernel mode, sig: 5 [#1]
NIP: 10000094 LR: 10000094 CTR: C001CBF4
REGS: d1072e90 TRAP: 0700 Not tainted (2.6.19.2-eldk-xm.1.0)
MSR: 00021000 <ME> CR: 00000000 XER: 00000000
TASK = cf31dc70[809385534] '�1� �˸' THREAD: c001ca38
GPR00: 00000000 D1072F40 C0555B70 10000094 C02C41C0 D1066000 10000094 D106C000
GPR08: C02CCAE4 D106A000 28000022 00021000 00000000 00000000 00000000 00000000
GPR16: 00000000 00000000 00000000 00000000 00000000 00000000 00000000 00000000
GPR24: 00000000 00000000 00000000 00000000 00000000 00000000 00000000 00000000
NIP [10000094] 0x10000094
LR [10000094] 0x10000094
Call Trace:
Instruction dump:
XXXXXXXX XXXXXXXX XXXXXXXX XXXXXXXX XXXXXXXX XXXXXXXX XXXXXXXX XXXXXXXX
XXXXXXXX XXXXXXXX XXXXXXXX XXXXXXXX XXXXXXXX XXXXXXXX XXXXXXXX XXXXXXXX
Oops: kernel access of bad area, sig: 11 [#2]
NIP: C00598C8 LR: C000A108 CTR: C001C2A4
REGS: d1072060 TRAP: 0300 Not tainted (2.6.19.2-eldk-xm.1.0)
MSR: 00021000 <ME> CR: 84000044 XER: 00000000
DAR: 3E20736D, DSISR: 00000000
TASK = cf31dc70[809385534] '�1� �˸' THREAD: c001ca38
GPR00: C000A0FC D1072110 CF31DC70 3E207365 3E20736D 00000000 00000000 C0240000
GPR08: CF31DD14 D1072000 00021002 C0002038 C001CBE8 00000000 00000000 00000000
GPR16: 00000000 00000000 00000000 00000000 00000000 00000000 00000000 00000000
GPR24: CF31DD48 00000000 D10721E0 3E20736D 00000000 CF31DD14 CF31DD48 00000000
NIP [C00598C8] find_vma+0x24/0x90
LR [C000A108] do_page_fault+0x50/0x3e0
Call Trace:
Instruction dump:
4c9d0020 91230020 4e800020 7c681b79 38600000 4d820020 4800000c 7d2a4b78
48000070 80680008 2f830000 419e001c <80030008> 7f802040 409d0010 80030004
Kernel panic - not syncing: Aiee, killing interrupt handler!
<0>Rebooting in 180 seconds..
Does that mean we can not call user space entry code directly, can we?
Regards,
Wang
--
Wang, Baojun Lanzhou University
Distributed & Embedded System Lab http://dslab.lzu.edu.cn
School of Information Science and Engeneering wangbj@lzu.edu.cn
Tianshui South Road 222. Lanzhou 730000 .P.R.China
Tel:+86-931-8912025 Fax:+86-931-8912022
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reply other threads:[~2007-10-30 11:45 UTC|newest]
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