Re: [PATCH] io stalls

[Nick Piggin <piggin@cyberone.com.au>]

Andrea Arcangeli wrote:

>On Wed, Jun 11, 2003 at 02:27:13PM -0400, Chris Mason wrote:
>
>>On Wed, 2003-06-11 at 14:12, Andrea Arcangeli wrote:
>>
>>>On Wed, Jun 11, 2003 at 01:42:41PM -0400, Chris Mason wrote:
>>>
>>>>+		if (q->rq[rw].count >= q->batch_requests) {
>>>>+			smp_mb();
>>>>+			if (waitqueue_active(&q->wait_for_requests[rw]))
>>>>+				wake_up(&q->wait_for_requests[rw]);
>>>>
>>>in my tree I also changed this to:
>>>
>>>				wake_up_nr(&q->wait_for_requests[rw], q->rq[rw].count);
>>>
>>>otherwise only one waiter will eat the requests, while multiple waiters
>>>can eat requests in parallel instead because we freed not just 1 request
>>>but many of them.
>>>
>>I tried a few variations of this yesterday and they all led to horrible
>>latencies, but I couldn't really explain why.  I had a bunch of other
>>
>
>the I/O latency in theory shouldn't change, we're not reordering the
>queue at all, they'll go to sleep immediatly again if __get_request
>returns null.
>

And go to the end of the queue?

>
>>stuff in at the time to try and improve throughput though, so I'll try
>>it again.
>>
>>I think part of the problem is the cascading wakeups from
>>get_request_wait_wakeup().  So if we wakeup 32 procs they in turn wakeup
>>another 32, etc.
>>
>
>so maybe it's enough to wakeup count / 2 to account for the double
>wakeup? that will avoid some overscheduling indeed.
>
>

Andrea, this isn't needed because when the queue falls below
the batch limit, every retiring request will do a wake up and
another request will be put on (as long as the waitqueue is
active).