[LARTC] About HFSC ?

[LARTC] About HFSC ?

[Sébastien CRAMATTE]

Hello,

I’ve read this Article avout VOIP and HFSC
http://automatthias.wordpress.com/2006/06/30/hfsc-and-voip/

I’ve got few questions ?

Considering this

tc class add dev $DEV parent 1:1 classid 1:2 hfsc \
rt m1 ${UPLINK}kbit d 50ms m2 $[1*$UPLINK/10]kbit \
ls m1 ${UPLINK}kbit d 50ms m2 $[3*$UPLINK/10]kbit \
ul rate ${UPLINK}kbit

rt = realtime curve
ls = linksharing curve

but
m1 = ?
m2 = ?
d = dmax ?

I’ve found this article too
http://linux-ip.net/articles/hfsc.en/

And for example this line is quite diferent !

tc class add dev eth0 parent 1:10 classid 1:12 hfsc sc umax 1500b dmax
30ms rate 100kbit ul rate 1000kbit

Does anyone could you light me ?

Regards

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Re: [LARTC] About HFSC ?

[Andy Furniss]

Sébastien CRAMATTE wrote:
> Hello,
> 
> I’ve read this Article avout VOIP and HFSC
> http://automatthias.wordpress.com/2006/06/30/hfsc-and-voip/
> 
> I’ve got few questions ?
> 
> Considering this
> 
> tc class add dev $DEV parent 1:1 classid 1:2 hfsc \
> rt m1 ${UPLINK}kbit d 50ms m2 $[1*$UPLINK/10]kbit \
> ls m1 ${UPLINK}kbit d 50ms m2 $[3*$UPLINK/10]kbit \
> ul rate ${UPLINK}kbit

That command and the script look a bit iffy to me - but then I could be 
wrong and often am :-)

> 
> rt = realtime curve
> ls = linksharing curve
> 
> but
> m1 = ?

m1 = slope/rate of the first part of the curve.

> m2 = ?

m2 = slope/rate of the second part.

> d = dmax ?

I think they will be equal if m1>m2, but not if m1<m2. dmax is a time 
when used with umax bytes hfsc will calculate the m1 bitrate needed to 
send a packet umax bytes long with a delay of dmax. d is the point on 
the x axis where m1 ends and m2 starts. If m1<m2 then d is still d but 
not the same as dmax.

Look at the curves on p10 of the sigcom pdf - I think xi = d
http://trash.net/~kaber/hfsc/SIGCOM97.pdf

You can use either format with linux, when you do tc -s -d class ls ... 
the output will be in m1 d m2 format.

Andy.
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