[RFC PATCH v2 2/4] Documentation: arm64/arm: dt bindings for numa.

[hanjun.guo@linaro.org (Hanjun Guo)]

Hi Arnd,

On 2014?12?10? 18:57, Arnd Bergmann wrote:
> On Wednesday 26 November 2014 17:12:49 Hanjun Guo wrote:
>>
>> Thanks for the detail information. I have the concerns about the distance
>> for NUMA nodes, does the "ibm,associativity-reference-points" property can
>> represent the distance between NUMA nodes?
>>
>> For example, a system with 4 sockets connected like below:
>>
>> Socket 0  <---->  Socket 1  <---->  Socket 2  <---->  Socket 3
>>
>> So from socket 0 to socket 1 (maybe on the same board), it just need 1
>> jump to access the memory, but from socket 0 to socket 2/3, it needs
>> 2/3 jumps and the *distance* relative longer. Can
>> "ibm,associativity-reference-points" property cover this?
>>
>
> Hi Hanjun,
>
> I only today found your replies in my spam folder, I need to put you on
> a whitelist so that doesn't happen again.

Thanks. I hope my ACPI patches will not scare your email filter :)

>
> The above topology is not easy to represent, but I think it would work
> like this (ignoring the threads/cores/clusters on the socket, which
> would also need to be described in a full DT), using multiple logical
> paths between the nodes:
>
> socket 0
> ibm,associativity = <0 0 0 0>, <1 1 1 0>, <2 2 0 0>, <3 0 0 0>;
>
> socket 1
> ibm,associativity = <1 1 1 1>, <0 0 0 1>, <2 2 2 1>, <3 3 1 1>;
>
> socket 2
> ibm,associativity = <2 2 2 2>, <0 0 2 2>, <1 1 1 2>, <3 3 3 2>;
>
> socket 3
> ibm,associativity = <3 3 3 3>, <0 3 3 3>, <1 1 3 3>, <2 2 2 3>;
>
> This describes four levels or hierarchy, with the lowest level
> being a single CPU core on one socket, and four paths between
> the sockets. To compute the associativity between two sockets,
> you need to look at each combination of paths to find the best
> match.
>
> Comparing sockets 0 and 1, the best matches are <1 1 1 0>
> with <1 1 1 1>, and <0 0 0 0> with <0 0 0 1>. In each case, the
> associativity is "3", meaning the first three entries match.
>
> Comparing sockets 0 and 3, we have four equally bad matches
> that each only match in the highest-level domain, e.g. <0 0 0 0>
> with <0 3 3 3>, so the associativity is only "1", and that means
> the two nodes are less closely associated than two neighboring
> ones.
>
> With the algorithm that powerpc uses to turn associativity into
> distance, 2**(numlevels - associativity), this would put the
> distance of neighboring nodes at "2", and the longest distance
> at "8".

Thanks for the explain, I can understand how it works now,
a bit complicated for me and I think the distance property
"node-matrix" in Ganapatrao's patch is straight forward,
what do you think?

Thanks
Hanjun