Flexible I/O Tester development
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From: Jens Axboe <jens.axboe@oracle.com>
To: Learner Study <learner.study@gmail.com>
Cc: fio@vger.kernel.org
Subject: Re: Ques on FIO output (how to interpret iops)
Date: Sat, 20 Jun 2009 08:27:03 +0200	[thread overview]
Message-ID: <20090620062702.GI31415@kernel.dk> (raw)
In-Reply-To: <7efa8a7d0906191519l5b268430o3ec4c96e60dfcb7a@mail.gmail.com>

On Fri, Jun 19 2009, Learner Study wrote:
> Hi:
> 
> How do I calculate total IOPS done by different FIO threads/jobs?
> 
> Following is output from FIO (with two threads)...
> 
> Each thread shows "bw" and "iops" numbers. Towards the end of output log,
> there is "aggrb" which is sum of individual "bw" of threads, but "io" field
> (3 line from the bottom of output below) doesn't seem to be sum of
> individual thread iops....
> 
> For example, Thread_1 has bw: 15k iops: 29366
> Thread_2 has bw: 15k iops: 29445
> But, the summary towards the end (third line from bottom of output), says
> "io=1,723MiB, aggrb=30,105KiB/s".
> 
> In this aggrb is good but io doesn't match up (it should be 58781) ! Can
> someone please educate what am I missing?

Can you try a newer version? If the problem is still there, the best way
to get it fixed is to send my a simple job file that reproduces the
problem, and then I can easily fix it for you.

-- 
Jens Axboe


  reply	other threads:[~2009-06-20  6:27 UTC|newest]

Thread overview: 9+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2009-06-19 22:19 Ques on FIO output (how to interpret iops) Learner Study
2009-06-20  6:27 ` Jens Axboe [this message]
2009-06-20 13:21   ` John Cagle
2009-06-20 14:12     ` Jens Axboe
2009-06-20 20:38       ` Learner Study
2009-06-20 21:17         ` Learner Study
     [not found]           ` <6863f0c90906202031h54c9f74bwdb09ca084d05ddfa@mail.gmail.com>
2009-06-21  5:15             ` Learner Study
2009-06-21 12:30               ` John Cagle
2009-06-20 15:33     ` Jens Axboe

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