Re: Ques on FIO output (how to interpret iops)

[Jens Axboe <axboe@kernel.dk>]

On 20/06/2009, at 15.21, John Cagle <jcagle@gmail.com> wrote:

> On Sat, Jun 20, 2009 at 1:27 AM, Jens Axboe <jens.axboe@oracle.com>  
> wrote:
> On Fri, Jun 19 2009, Learner Study wrote:
> > Hi:
> >
> > How do I calculate total IOPS done by different FIO threads/jobs?
> >
> > Following is output from FIO (with two threads)...
> >
> > Each thread shows "bw" and "iops" numbers. Towards the end of  
> output log,
> > there is "aggrb" which is sum of individual "bw" of threads, but  
> "io" field
> > (3 line from the bottom of output below) doesn't seem to be sum of
> > individual thread iops....
> >
> > For example, Thread_1 has bw: 15k iops: 29366
> > Thread_2 has bw: 15k iops: 29445
> > But, the summary towards the end (third line from bottom of  
> output), says
> > "io=1,723MiB, aggrb=30,105KiB/s".
> >
> > In this aggrb is good but io doesn't match up (it should be  
> 58781) ! Can
> > someone please educate what am I missing?
>
> Can you try a newer version? If the problem is still there, the best  
> way
> to get it fixed is to send my a simple job file that reproduces the
> problem, and then I can easily fix it for you.
>
> I thought the "io=" summary at the end was the total amount of I/O  
> performed (in megabytes), not the total number of IOPS.

It is, you are correct. Seems I misread the problem.