[Linux-ia64] ABI change in gcc for ia64?

[Linux-ia64] ABI change in gcc for ia64?

[John Kohl]

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Was there an ABI change for gcc for ia64 between 
"old":	    gcc version 2.9-ia64-000216-final
"new":	    gcc version 2.96-ia64-000717 snap 001117

We are seeing interoperation failures between code compiled with these
two versions, related to structure passing (thankfully, user-space only
for now).

I've got a test case which shows this:

caller (tv1.c)	    callee (blah.c)	result
old		    old	   		OK
old		    new			BAD
new		    old			BAD
new		    new			OK


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#include <sys/types.h>
#include <sys/socket.h>
#include <sys/time.h>

extern void blah(
    struct sockaddr_in *__raddr,
    u_long __program,
    u_long __version,
    struct timeval __wait_resend,
    int *__sockp
);

char carray[] = "Hi there.\n";

main()
{
    struct timeval tv;
    char *cp = carray;
    int i = 37;

    tv.tv_sec = 1;
    tv.tv_usec = 2;

    blah(NULL, 32, 33, tv, &i);
}


[-- Attachment #3: ~/src/tv-test/blah.c --]
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#include <sys/types.h>
#include <sys/socket.h>
#include <sys/time.h>

extern void
blah(
    struct sockaddr_in *__raddr,
    u_long __program,
    u_long __version,
    struct timeval __wait_resend,
    int *__sockp
);

extern void
blah(
    struct sockaddr_in *__raddr,
    u_long __program,
    u_long __version,
    struct timeval tv,
    int *ip
)
{
    printf("raddr = %p\n", __raddr);
    printf("prog = %d\nvers = %d\n", __program, __version);
    printf("tv.tv_sec = %d\ntv.tv_usec = %d\nip = %p\n",
           tv.tv_sec, tv.tv_usec, ip);
    printf("int = %d\n", *ip);
}