Re: [PATCH 1/3] rust: sync: return `Result<&T, T>` from `SetOnce::populate()`

Re: [PATCH 1/3] rust: sync: return `Result<&T, T>` from `SetOnce::populate()`

[sashiko-bot]

Thank you for your contribution! Sashiko AI review found 1 potential issue(s) to consider:

Pre-existing issues:
- [High] `ModuleParamAccess` lacks `#[repr(C)]`, leading to potential Undefined Behavior and memory corruption when its pointer is cast to `SetOnce<T>`.
--

--- Patch [1]: [PATCH 1/3] rust: sync: return `Result<&T, T>` from `SetOnce::populate()` ---
commit e0d10f7a2c42bcda24ee9851cc2fda3d4c4bc480
Author: Alice Ryhl <aliceryhl@google.com>

rust: sync: return Result<&T, T> from SetOnce::populate()

This commit changes the return value of SetOnce::populate() from a boolean
to a Result to allow infallible access to the inserted value on success.
It also ensures the inserted value is not dropped under a lock if populate()
fails, and updates ModuleParam and Binder to handle the new return type.

> diff --git a/rust/kernel/module_param.rs b/rust/kernel/module_param.rs
> index 6541af218390c..8f0bd085badfe 100644
> --- a/rust/kernel/module_param.rs
> +++ b/rust/kernel/module_param.rs
> @@ -77,10 +77,10 @@ pub trait ModuleParam: Sized + Copy {
>          // SAFETY: By function safety requirements, this access is safe.
>          let container = unsafe { &*((*param).__bindgen_anon_1.arg.cast::<SetOnce<T>>()) };

[Severity: High]
This is a pre-existing issue, but since we are modifying this code block, is
it safe to cast this void pointer directly to SetOnce<T>?

Looking at the definition of ModuleParamAccess<T>, it lacks a #[repr(C)]
annotation:

rust/kernel/module_param.rs:ModuleParamAccess {
    value: SetOnce<T>,
    default: T,
}

Since it uses the default Rust layout, the compiler is free to reorder these
fields. When as_void_ptr() passes a pointer to the entire struct into the
C kernel parameters API:

rust/kernel/module_param.rs:ModuleParamAccess::as_void_ptr() {
    core::ptr::from_ref(self).cast_mut().cast()
}

And set_param casts it back directly to SetOnce<T> (assuming it sits at
offset 0), could this lead to memory corruption if the compiler decides to
place default before value?

> -        container
> -            .populate(new_value)
> -            .then_some(0)
> -            .ok_or(kernel::error::code::EEXIST)
> +        match container.populate(new_value) {
> +            Ok(_) => Ok(0),
> +            Err(_) => Err(EEXIST),
> +        }
>      })
>  }

-- 
Sashiko AI review · https://sashiko.dev/#/patchset/20260722-setonce-populate-v1-0-fa7455c26c42@google.com?part=1

Re: [PATCH 2/3] rust: sync: add SetOnce::try_get_or_populate()

[sashiko-bot]

Thank you for your contribution! Sashiko AI review found 1 potential issue(s) to consider:
- [High] Optimistic, unlocked execution of the initialization closure `f()` leads to duplicate side-effects and spurious TOCTOU initialization failures.
--

--- Patch [2]: [PATCH 2/3] rust: sync: add SetOnce::try_get_or_populate() ---
commit fa04209af44f9b7b6642f550eaec6a8a1f95a58a
Author: Alice Ryhl <aliceryhl@google.com>

rust: sync: add SetOnce::try_get_or_populate()

This commit introduces a try_get_or_populate() helper to SetOnce. The new
method allows callers to use a user-provided lock to avoid spinning on the
internal atomic state during concurrent initialization.

> diff --git a/rust/kernel/sync/set_once.rs b/rust/kernel/sync/set_once.rs
> index a78f8c8e87dbf..d9cc598a8d78f 100644
> --- a/rust/kernel/sync/set_once.rs
> +++ b/rust/kernel/sync/set_once.rs

[ ... ]

> @@ -104,6 +111,34 @@ pub fn populate(&self, value: T) -> Result<&T, T> {
>          }
>      }
>  
> +    /// Get the value, or populate it if it's missing.
> +    ///
> +    /// This method is useful to avoid spinning on the internal atomic state. If all writers call
> +    /// this method with the same lock, then they are synchronized with each other and it's
> +    /// guaranteed that no caller will attempt to invoke [`SetOnce::populate`] more than once.
> +    pub fn try_get_or_populate<F, E, U, B>(&self, lock: &lock::Lock<U, B>, f: F) -> Result<&T, E>
> +    where
> +        B: lock::Backend,
> +        F: FnOnce() -> Result<T, E>,
> +    {
> +        if let Some(value) = self.as_ref() {
> +            return Ok(value);
> +        }
> +
> +        let mut to_insert = f()?;
         ^^^^

[Severity: High]
Could this introduce a regression where evaluating f() outside the lock
risks duplicate side-effects?

If multiple threads call try_get_or_populate() concurrently on an
uninitialized SetOnce, they could both bypass the initial as_ref() check
and execute f() simultaneously. If f() performs operations like allocating
hardware resources or registering IDs, wouldn't those occur multiple times
before reaching the lock?

Additionally, if thread A successfully initializes the value inside the lock
but thread B subsequently fails during its concurrent evaluation of f(), the
? operator will immediately return the error. Does this cause thread B to
erroneously fail and propagate the error, even though the SetOnce is now
fully populated by thread A?

> +        loop {
> +            if let Some(value) = self.as_ref() {
> +                return Ok(value);
> +            }
> +
> +            let _guard = lock.lock();
> +            match self.populate(to_insert) {
> +                Ok(value) => return Ok(value),
> +                Err(ret) => to_insert = ret,
> +            }
> +        }
> +    }

-- 
Sashiko AI review · https://sashiko.dev/#/patchset/20260722-setonce-populate-v1-0-fa7455c26c42@google.com?part=2