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From: ichi@ihug.co.nz
To: wolfgang <wolfgang127jp@ybb.ne.jp>
Cc: linux-newbie@vger.kernel.org
Subject: Re: what's ${1##*/}
Date: Sat, 21 Dec 2002 14:52:45 +0000	[thread overview]
Message-ID: <3E04803D.D79BC7E@ihug.co.nz> (raw)
In-Reply-To: 20021221084841.659D.WOLFGANG127JP@ybb.ne.jp

wolfgang wrote:
> 
> I found the statement below in killproc() of 
> /etc/init.d/functions script.
> 
> base=${1##*/}

This is a bash structure used to remove parts of a 
variable.  The variable is $1.  The ##*/ means that 
everything before the last / is removed.  Therefore,
if $1 is the full pathname of a file, $base will be
the filename (without the path).

Cheers,
Steven

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      reply	other threads:[~2002-12-21 14:52 UTC|newest]

Thread overview: 2+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2002-12-20 23:52 what's ${1##*/} wolfgang
2002-12-21 14:52 ` ichi [this message]

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