Re: kmemcheck caught read from freed memory (cfq_free_io_context)

[Jens Axboe <jens.axboe@oracle.com>]

On Wed, Apr 02 2008, Peter Zijlstra wrote:
> On Wed, 2008-04-02 at 13:32 +0200, Jens Axboe wrote:
> > On Wed, Apr 02 2008, Peter Zijlstra wrote:
> > > On Wed, 2008-04-02 at 13:14 +0200, Jens Axboe wrote:
> > > > On Wed, Apr 02 2008, Peter Zijlstra wrote:
> > > > > On Wed, 2008-04-02 at 13:07 +0200, Jens Axboe wrote:
> > > > > > On Wed, Apr 02 2008, Pekka Enberg wrote:
> > > > > > > Hi Paul,
> > > > > > > 
> > > > > > > On Wed, Apr 2, 2008 at 1:55 PM, Paul E. McKenney
> > > > > > > <paulmck@linux.vnet.ibm.com> wrote:
> > > > > > > >  I will check this when I get back to some bandwidth -- but in the meantime,
> > > > > > > >  does kmemcheck special-case SLAB_DESTROY_BY_RCU?  It is legal to access
> > > > > > > >  newly-freed items in that case, as long as you did rcu_read_lock()
> > > > > > > >  before gaining a reference to them and don't hold the reference past
> > > > > > > >  the matching rcu_read_unlock().
> > > > > > > 
> > > > > > > No, kmemcheck is work in progress and does not know about
> > > > > > > SLAB_DESTROY_BY_RCU yet. The reason I asked Vegard to post the warning
> > > > > > > was because Peter, Vegard, and myself identified this particular
> > > > > > > warning as a real problem. But yeah, kmemcheck can cause false
> > > > > > > positives for RCU for now.
> > > > > > 
> > > > > > Makes sense, and to me Pauls analysis of the code looks totally correct
> > > > > > - there's no bug there, at least related to hlist traversal and
> > > > > > kmem_cache_free(), since we are under rcu_read_lock() and thus hold off
> > > > > > the grace for freeing.
> > > > > 
> > > > > but what holds off the slab allocator re-issueing that same object and
> > > > > someone else writing other stuff into it?
> > > > 
> > > > Nothing, that's how rcu destry works here. But for the validation to be
> > > > WRONG radix_tree_lookup(..., old_key) must return cic for new_key, not
> > > > NULL.
> > > > 
> > > 
> > > 
> > > 	A				B			C
> > > 
> > > cfq_cic_lookup(cfqd_1, ioc)
> > > 
> > >   rcu_read_lock()
> > >   cic = radix_tree_lookup(, cfqd_q);
> > > 
> > > 					cfq_cic_free()
> > >   					
> > > 								cfq_cic_link(cfqd_2, ioc,)
> > > 
> > >   rcu_read_unlock()
> > > 
> > > 
> > > and now we have that:
> > > 
> > >   cic->key == cfqd_2
> > > 
> > > 
> > > I'm not seeing anything stopping this from happening.
> > 
> > I don't follow your A-B-C here, what do they refer to?
> 
> A does a radix_tree_lookup() of cfqd_1 (darn typos)
> B does a kfree of the same cic found by A
> C does an alloc and gets the same cic as freed by B and inserts it
>   in a different location.
> 
> So that when we return to A, cic->key == cfqd_2 even though we did a
> lookup for cfqd_1.

That I follow, my question was if A, B, and C refer to different
processes but with a shared io context? I'm assuming that is correct...

And it does look buggy. It looks my assumption of what slab rcu destroy
did is WRONG, it should be replaced by a manual call_rcu() freeing
instead.

-- 
Jens Axboe