Re: [PATCH v3 02/31] arm64: Kernel booting and initialisation

[Jean-Christophe PLAGNIOL-VILLARD <plagnioj@jcrosoft.com>]

On 19:29 Sun 09 Sep     , Nicolas Pitre wrote:
> On Sun, 9 Sep 2012, Jean-Christophe PLAGNIOL-VILLARD wrote:
> 
> > On 17:26 Fri 07 Sep     , Catalin Marinas wrote:
> > > +4. Call the kernel image
> > > +------------------------
> > > +
> > > +Requirement: MANDATORY
> > > +
> > > +The decompressed kernel image contains a 32-byte header as follows:
> > > +
> > > +  u32 magic	= 0x14000008;	/* branch to stext, little-endian */
> > > +  u32 res0	= 0;		/* reserved */
> > > +  u64 text_offset;		/* Image load offset */
> > > +  u64 res1	= 0;		/* reserved */
> > > +  u64 res2	= 0;		/* reserved */
> > we need to have a magic to known it's a arm64 kernel
> 
> You have it: it's 0x14000008 at the beginning.
fragile
> 
> > > +
> > > +The image must be placed at the specified offset (currently 0x80000)
> > > +from the start of the system RAM and called there. The start of the
> > > +system RAM must be aligned to 2MB.
> > can we drop this
> 
> Drop what?
> And why?
This contrain the must be loadable at any address

Best Regards,
J.